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I am having a basic doubt regarding IF statement. Let's say I want to match string SUN with a character array(size 3).
if(arr[0]!='S' || arr[1]!='U' || arr[2]!='N')
cout << "no";
else
cout<< "yes";
Are all conditions checked in If statement or does it return true on first mismatch?
If all conditions are checked, will the the order of checking be from right to left?
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When you combine each one of them with an IF statement, they read like this: AND – =IF(AND(Something is True, Something else is True), Value if True, Value if False) OR – =IF(OR(Something is True, Something else is True), Value if True, Value if False) NOT – =IF(NOT(Something is True), Value if True, Value if False)
A nested if statement is an if statement placed inside another if statement. Nested if statements are often used when you must test a combination of conditions before deciding on the proper action.
The multiple IF conditions in Excel are IF statements contained within another IF statement. They are used to test multiple conditions simultaneously and return distinct values. The additional IF statements can be included in the “value if true” and “value if false” arguments of a standard IF formula.
You can automate the evaluation of logical tests by NESTING the AND, OR, NOT functions inside a single IF function. This means that if we have multiple conditions but we want to return a single output, we can nest any of the conjunction functions inside an IF and specify outputs accordingly.
According to the C++ Standard
1 The && operator groups left-to-right. The operands are both contextually converted to bool (Clause 4). The result is true if both operands are true and false otherwise. Unlike &, && guarantees left-to-right evaluation: the second operand is not evaluated if the first operand is false.
and
1 The || operator groups left-to-right. The operands are both contextually converted to bool (Clause 4). It returns true if either of its operands is true, and false otherwise. Unlike |, || guarantees left-to-right evaluation; moreover, the second operand is not evaluated if the first operand evaluates to true.
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