Multiline python regex

Question

I have a file structured like this :

A: some text
B: more text
even more text
on several lines
A: and we start again
B: more text
more
multiline text

I'm trying to find the regex that will split my file like this :

>>>re.findall(regex,f.read())
[('some text','more text','even more text\non several lines'),
 ('and we start again','more text', 'more\nmultiline text')]

So far, I've ended up with the following :

>>>re.findall('A:(.*?)\nB:(.*?)\n(.*?)',f.read(),re.DOTALL)
[(' some text', ' more text', ''), (' and we start again', ' more text', '')]

The multiline text is not catched. I guess is because the lazy qualifier is really lazy and catch nothing, but I take it out, the regex gets really greedy :

>>>re.findall('A:(.*?)\nB:(.*?)\n(.*)',f.read(),re.DOTALL)
[(' some text',
' more text',
'even more text\non several lines\nA: and we start again\nB: more text\nmore\nmultiline text')]

Does any one has an idea ? Thanks !

Answer 1

You could tell the regex to stop matching at the next line that starts with A: (or at the end of the string):

re.findall(r'A:(.*?)\nB:(.*?)\n(.*?)(?=^A:|\Z)', f.read(), re.DOTALL|re.MULTILINE)