I am running R on an Ubuntu workstation with 8 virtual cores and 8 Gb of ram. I was hoping to routinely use the multicore package to make use of the 8 cores in parallel; however I find that the whole R process becomes duplicated 8 times. As R actually seems to use much more memory than is reported in gc (by a factor 5, even after gc()), this means that even a relatively mild memory usage (one 200Mb object) becomes intractably memory-heavy once duplicated 8 times. I looked into bigmemory to have the child processes share the same memory space; but it would require some major rewriting of my code as it doesn't deal with dataframes.
Is there a way to make R as lean as possible before forking, i.e. have the OS reclaim as much memory as possible?
EDIT: I think I understand what is going on now. The problem is not where I thought it was -- objects that exist in the parent thread and are not manipulated do not get duplicated eight times. Instead my problem, I believe, came from the nature of the manipulation I am making each child process perform. Each has to manipulate a big factor with hundreds of thousands of levels, and I think this is the memory-heavy bit. As a result, it is indeed the case that the overall memory load is proportional to the number of cores; but not as dramatically as I thought. Another lesson I learned is that with 4 physical cores + possibility of hyperthreading, hyperthreading is actually not typically a good idea for R. The gain is minimal, and the memory cost may be non-trivial. So I'll be working on 4 cores from now on.
For those who would like to experiment, this is the type of code I was running:
# Create data
sampdata <- data.frame(id = 1:1000000)
for (letter in letters) {
sampdata[, letter] <- rnorm(1000000)
}
sampdata$groupid = ceiling(sampdata$id/2)
# Enable multicore
library(multicore)
options(cores=4) # number of cores to distribute the job to
# Actual job
system.time(do.call("cbind",
mclapply(subset(sampdata, select = c(a:z)), function(x) tapply(x, sampdata$groupid, sum))
))
Have you tried data.table?
> system.time(ans1 <- do.call("cbind",
lapply(subset(sampdata,select=c(a:z)),function(x)tapply(x,sampdata$groupid,sum))
))
user system elapsed
906.157 13.965 928.645
> require(data.table)
> DT = as.data.table(sampdata)
> setkey(DT,groupid)
> system.time(ans2 <- DT[,lapply(.SD,sum),by=groupid])
user system elapsed
186.920 1.056 191.582 # 4.8 times faster
> # massage minor diffs in results...
> ans2$groupid=NULL
> ans2=as.matrix(ans2)
> colnames(ans2)=letters
> rownames(ans1)=NULL
> identical(ans1,ans2)
[1] TRUE
Your example is very interesting. It is reasonably large (200MB), there are many groups (1/2 million), and each group is very small (2 rows). The 191s can probably be improved by quite a lot, but at least it's a start. [March 2011]
And now, this idiom (i.e. lapply(.SD,...)
) has been improved a lot. With v1.8.2, and on a faster computer than the test above, and with the latest version of R etc, here is the updated comparison :
sampdata <- data.frame(id = 1:1000000)
for (letter in letters) sampdata[, letter] <- rnorm(1000000)
sampdata$groupid = ceiling(sampdata$id/2)
dim(sampdata)
# [1] 1000000 28
system.time(ans1 <- do.call("cbind",
lapply(subset(sampdata,select=c(a:z)),function(x)
tapply(x,sampdata$groupid,sum))
))
# user system elapsed
# 224.57 3.62 228.54
DT = as.data.table(sampdata)
setkey(DT,groupid)
system.time(ans2 <- DT[,lapply(.SD,sum),by=groupid])
# user system elapsed
# 11.23 0.01 11.24 # 20 times faster
# massage minor diffs in results...
ans2[,groupid:=NULL]
ans2[,id:=NULL]
ans2=as.matrix(ans2)
rownames(ans1)=NULL
identical(ans1,ans2)
# [1] TRUE
sessionInfo()
R version 2.15.1 (2012-06-22)
Platform: x86_64-pc-mingw32/x64 (64-bit)
locale:
[1] LC_COLLATE=English_United Kingdom.1252 LC_CTYPE=English_United Kingdom.1252
[3] LC_MONETARY=English_United Kingdom.1252 LC_NUMERIC=C
[5] LC_TIME=English_United Kingdom.1252
attached base packages:
[1] stats graphics grDevices datasets utils methods base
other attached packages:
[1] data.table_1.8.2 RODBC_1.3-6
Things I've tried on Ubuntu 64 bit R, ranked in order of success:
Work with fewer cores, as you are doing.
Split the mclapply jobs into pieces, and save the partial results to a database using DBI with append=TRUE.
Use the rm
function along with gc()
often
I have tried all of these, and mclapply still begins to create larger and larger processes as it runs, leading me to suspect each process is holding onto some sort of residual memory it really doesn't need.
P.S. I was using data.table, and it seems each child process copies the data.table.
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