I'm trying to convert an makefile-build to cmake (to avoid the current state of being forced to take care for the windows-build env based on make/msdev and the linux based on make/gcc).
In this project, I've found a directory full of sourcecode files that get, based on a naming convention, compiled to libraries. (e.g. c1223.c => c1223.dll (or .sl) )
The current makefile consists of some directives using wildcards, e.g.:
LIB_NO = $(basename $(subst s,,$@))
OBJ = $(OBJ_PATH)/s$(LIB_NO).o $(OBJ_PATH)/c$(LIB_NO).o\
$(OBJ_PATH)/b$(LIB_NO).o
$(OBJ_PATH)/%.o : %.c
-$(CC) $(CFLAGS) -I$(PWD) -c $< -o $@
-(chmod a+w $@;true)
I've searched for a while but can't find anything that seems to work. Is it even possible with cmake to let it generate a wildcard based build?
Any comments, hints and suggestions are very welcome :)
cheers Markus
You can use fairly primitive globbing (there's no regular expression syntax that I can see).
file(GLOB TESTSRCS "test/src/*.cpp")
# Compile the test sources.
add_executable(Tests ${TESTSRCS})
target_link_libraries(Tests ${LIB} gtest gtest_main)
The actual makefiles do not seem to contain wildcard searches inside them. If you add new files you will need to re-run cmake.
What I don't know is how you would manage to wrap up the library creation in a single macro if you have many different library files to generate.
You might be able to do something like this if there's only one c file per library:
file(GLOB libfiles "path/to/libs/c*.c")
foreach(libfile ${libfiles})
GET_FILENAME_COMPONENT(libname ${libfile} NAME) # remove the '.c' part (untested, hopefully this will work)
add_library(${libname} ${libfile})
endforeach(libfile)
If anybody else has a better solution, I would also like to learn it.
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