Most efficient way to upload image to Amazon S3 with Python using Boto3

Question

I'm implementing Boto3 to upload files to S3, and all works fine. The process that I'm doing is the following:

I get base64 image from FileReader Javascript object. Then I send the base64 by ajax to the server, I decode the base64 image and I generate a random name to rename the key argument

data = json.loads(message['text'])
dec = base64.b64decode(data['image'])
s3 = boto3.resource('s3')
s3.Bucket('bucket_name').put_object(Key='random_generated_name.png', Body=dec,ContentType='image/png',ACL='public-read')

This works fine but respect to performance, is there a better way to improve it?

Answer 1

I used this and I believe its more effective and pythonic.

    import boto3
    s3 = boto3.client('s3')
    bucket = 'your-bucket-name'
    file_name = 'location-of-your-file'
    key_name = 'name-of-file-in-s3'
    s3.upload_file(file_name, bucket, key_name)