Most concise way to check whether a list is empty or contains only None?

Question

Most concise way to check whether a list is empty or contains only None?

I understand that I can test:

if MyList:
    pass

and:

if not MyList:
    pass

but what if the list has an item (or multiple items), but those item/s are None:

MyList = [None, None, None]
if ???:
    pass

Answer 1

One way is to use all and a list comprehension:

if all(e is None for e in myList):
    print('all empty or None')

This works for empty lists as well. More generally, to test whether the list only contains things that evaluate to False, you can use any:

if not any(myList):
    print('all empty or evaluating to False')