I have about 200 mongodb databases. Every database has a collection called 'Group' and in this collection there is a field called 'meldingId'.
Is it possible to make a one mongodb query which find all values in the different databases.
(I managed to select the databases bij looping through the databases by selectDB($database_name))
You can use MongoDB Shell or MongoDB Compass to create a new database. MongoDB provides the use <database-name command to connect with the database. If the specified database name does not exist then it creates it and set it as a current database.
It is not possible to query using lookup in two different db's. $lookup in mongodb supports Performs a left outer join to an unsharded collection in the same database. Save this answer.
You can query multiple collections using the $lookup aggregation. I wrote an example here on the forum. Also, the Query Results Data Source can absolutely join results from several MongoDB queries. It doesn't matter which source database you used.
Open a new database connection. Open a connection to a new server using new Mongo() . Use getDB() method of the connection to select a database.
In Mongo shell, this can be done by using db.getSiblingDB() method to switch to admin database and get a list of the 200 databases by running the admin command db.runCommand({ "listDatabases": 1 }). Iterate over the list of databases and use db.getSiblingDB() again to switch between databases, query the Group collection for the meldingId values. Something like this:
// Switch to admin database and get list of databases.
db = db.getSiblingDB("admin");
dbs = db.runCommand({ "listDatabases": 1 }).databases;
// Iterate through each database.
dbs.forEach(function(database) {
    db = db.getSiblingDB(database.name);
    // Get the Group collection
    collection = db.getCollection("Group");
    // Iterate through all documents in collection.
    /*
        collection.find().forEach(function(doc) {
            // Print the meldingId field.
            print(doc.meldingId);
        });
    */
    var meldingIds = collection.distinct('meldingId');
    print(meldingIds);
});
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