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have been searching for a mod operator in ios, just like the % in c, but no luck in finding it. Tried the answer in this link but it gives the same error.
I have a float variable 'rotationAngle' whose angle keeps incrementing or decrementing based on the users finger movement.
Some thing like this:
if (startPoint.x < pt.x) {
if (pt.y<936/2)
rotationAngle += pt.x - startPoint.x;
else
rotationAngle += startPoint.x - pt.x;
}
rotationAngle = (rotationAngle % 360);
}
I just need to make sure that the rotationAngle doesnot cross the +/- 360 limit. Any help any body. Thanks
839
The modulo operator, denoted by %, is an arithmetic operator. The modulo division operator produces the remainder of an integer division. produces the remainder when x is divided by y.
3) modulus operator is not just applicable to integral types e.g. byte, short, int, long but also to floating-point types like float and double. 4) You can also use the remainder operator to check if a number is even or odd, or if a year is leap year.
Swift has a dedicated remainder operator in the form of % , and it's used to return the remainder after dividing one number wholly into another. For example, 14 % 3 is 2, because you can fit four 3s into 14, and afterwards you have the remainder 2.
You can use fmod (for double) and fmodf (for float) of math.h:
#import <math.h>
rotationAngle = fmodf(rotationAngle, 360.0f);
Use the fmod function, which does a floation-point modulo, for definition see here: http://www.cplusplus.com/reference/clibrary/cmath/fmod/. Examples of how it works (with the return values):
fmodf(100, 360); // 100
fmodf(300, 360); // 300
fmodf(500, 360); // 140
fmodf(1600, 360); // 160
fmodf(-100, 360); // -100
fmodf(-300, 360); // -300
fmodf(-500, 360); // -140
fmodf takes "float" as arguments, fmod takes "double" and fmodl takes "double long", but they all do the same thing.
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