Iterate through alphabet in Swift

Question

in Obj-C it was possible to iterate through alphabet with:

for (char x='A'; x<='Z'; x++) {

In Swift this isn't possible. Any idea how I could do this?

Answer 1

In Swift, you can iterate chars on a string like this:

Swift 2

for char in "abcdefghijklmnopqrstuvwxyz".characters {
    println(char)
}

Swift 1.2

for char in "abcdefghijklmnopqrstuvwxyz" {
    println(char)
}

There might be a better way though.

Answer 2

It's slightly cumbersome, but the following works (Swift 3/4):

for value in UnicodeScalar("a").value...UnicodeScalar("z").value { print(UnicodeScalar(value)!) }

I suspect that the problem here is that the meaning of "a"..."z" could potentially be different for different string encodings.

---

(Older stuff)

Also cumbersome, but without the extra intermediate variable:

    for letter in map(UnicodeScalar("a").value...UnicodeScalar("z").value, {(val: UInt32) -> UnicodeScalar in return UnicodeScalar(val); })
    {
        println(letter)
    }

Answer 3

for i in 97...122{println(UnicodeScalar(i))}

Answer 4

Swift 4.2 version is much easier

for char in "abcdefghijklmnopqrstuvwxyz" {
    print(char)
}