I was trying to figure out how much memory I can malloc to maximum extent on my machine (1 Gb RAM 160 Gb HD Windows platform).
I read that the maximum memory malloc can allocate is limited to physical memory (on heap).
Also when a program exceeds consumption of memory to a certain level, the computer stops working because other applications do not get enough memory that they require.
So to confirm, I wrote a small program in C:
int main(){ int *p; while(1){ p=(int *)malloc(4); if(!p)break; } }
I was hoping that there would be a time when memory allocation would fail and the loop would break, but my computer hung as it was an infinite loop.
I waited for about an hour and finally I had to force shut down my computer.
Some questions:
Description. The malloc() function reserves a block of storage of size bytes. Unlike the calloc() function, malloc() does not initialize all elements to 0. The maximum size for a non-teraspace malloc() is 16711568 bytes.
Malloc(12) and malloc(16) allocate 16 bytes for the user, plus an extra 8 bytes for bookkeeping for a total of 24 bytes. Malloc(100) allocates 104 bytes for the user, plus an extra 8 bytes for bookkeeping.
In C, the library function malloc is used to allocate a block of memory on the heap. The program accesses this block of memory via a pointer that malloc returns. When the memory is no longer needed, the pointer is passed to free which deallocates the memory so that it can be used for other purposes.
malloc(10) allocates 10 bytes, which is enough space for 10 chars. To allocate space for 10 ints, you could call malloc(10 * sizeof(int)) .
I read that the maximum memory
malloc
can allocate is limited to physical memory (on heap).
Wrong: most computers/OSs support virtual memory, backed by disk space.
Some questions: does
malloc
allocate memory from HDD also?
malloc
asks the OS, which in turn may well use some disk space.
What was the reason for above behavior? Why didn't the loop break at any time?
Why wasn't there any allocation failure?
You just asked for too little at a time: the loop would have broken eventually (well after your machine slowed to a crawl due to the large excess of virtual vs physical memory and the consequent super-frequent disk access, an issue known as "thrashing") but it exhausted your patience well before then. Try getting e.g. a megabyte at a time instead.
When a program exceeds consumption of memory to a certain level, the computer stops working because other applications do not get enough memory that they require.
A total stop is unlikely, but when an operation that normally would take a few microseconds ends up taking (e.g.) tens of milliseconds, those four orders of magnitude may certainly make it feel as if the computer had basically stopped, and what would normally take a minute could take a week.
I know this thread is old, but for anyone willing to give it a try oneself, use this code snipped
#include <stdlib.h> int main() { int *p; while(1) { int inc=1024*1024*sizeof(char); p=(int*) calloc(1,inc); if(!p) break; } }
run
$ gcc memtest.c $ ./a.out
upon running, this code fills up ones RAM until killed by the kernel. Using calloc instead of malloc to prevent "lazy evaluation". Ideas taken from this thread: Malloc Memory Questions
This code quickly filled my RAM (4Gb) and then in about 2 minutes my 20Gb swap partition before it died. 64bit Linux of course.
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