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How do you get the maximum number of bytes that can be passed to a sendto(..) call for a socket opened as a UDP port?
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The maximum size, in bytes, of a buffer that stores messages while they are processed for an endpoint configured with this binding. The default value is 65,536 bytes.
The default buffer size is 8 KB. The maximum size is 8 MB (8096 KB). The optimal buffer size depends on several network environment factors including types of switches and systems, acknowledgment timing, error rates and network topology, memory size, and data transfer size.
The default send buffer size for UDP sockets is 65535 bytes. The default receive buffer size for UDP sockets is 2147483647 bytes.
The Send to feature, introduced with Windows 95, is an option in the Windows context menu when you right-click a file or folder. It "sends" a file to a program of your choice, opening the file with the program.
Use getsockopt(). This site has a good breakdown of the usage and options you can retrieve.
In Windows, you can do:
int optlen = sizeof(int); int optval; getsockopt(socket, SOL_SOCKET, SO_MAX_MSG_SIZE, (int *)&optval, &optlen);
For Linux, according to the UDP man page, the kernel will use MTU discovery (it will check what the maximum UDP packet size is between here and the destination, and pick that), or if MTU discovery is off, it'll set the maximum size to the interface MTU and fragment anything larger. If you're sending over Ethernet, the typical MTU is 1500 bytes.
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