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I have a string with possible \n in them. Think of:
Foo1
Foo2
Foo3 Foo4.
I want to replace 's at the start of each line, but the above is one string. ^nbsp; only matches the first before Foo1. I want to do at the start of any newline, look for . Any ideas?
So, I want a regex that'll match the first two 's above, but not the 3rd.
624
"\n" matches a newline character.
As usual, the regex engine starts at the first character: 7. The first token in the regular expression is ^. Since this token is a zero-length token, the engine does not try to match it with the character, but rather with the position before the character that the regex engine has reached so far.
They are called “anchors”. The caret ^ matches at the beginning of the text, and the dollar $ – at the end. The pattern ^Mary means: “string start and then Mary”.
The RegExp \B Metacharacter in JavaScript is used to find a match which is not present at the beginning or end of a word. If a match is found it returns the word else it returns NULL. Example 1: This example matches the word “for” which is not present at the beginning or end of the word.
You need to enable the multiline matching mode with /m flag, in order to match each line as a separate line.
/^(?: )+/gm
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