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I have a quick question about Regular Expressions.
Can I specify a pattern and have everything else that doesnt fit the pattern to be matched?
For example, anything that does not fit into this pattern: HT\d{4}, I want to consider a match.
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You can invert sets by adding a circumflex ^ at the beginning of the set. [^a] matches all except a and [^0-9] all everything else but digits. The circumflex is located on the key 6. In this regular expression, you can invert the set by adding a circumflex behind the first bracket.
To replace or remove characters that don't match a regex, call the replace() method on the string passing it a regular expression that uses the caret ^ symbol, e.g. /[^a-z]+/ .
The Match(String, String, RegexOptions, TimeSpan) method returns the first substring that matches a regular expression pattern in an input string. For information about the language elements used to build a regular expression pattern, see Regular Expression Language - Quick Reference.
'?' is also a quantifier. Is short for {0,1}. It means "Match zero or one of the group preceding this question mark." It can also be interpreted as the part preceding the question mark is optional. e.g.: pattern = re.compile(r'(\d{2}-)?\
yes, you can do this: (?!HT\d{4})
It's called a "negative lookahead". It is supported in most regex engines.
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