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How to parse a string in Java? Is there anything similar to Python's re.finditer()?

I have an input string with a very simple pattern - capital letter, integer, capital letter, integer, ... and I would like to separate each capital letter and each integer. I can't figure out the best way to do this in Java.

I have tried regexp using Pattern and Matcher, then StringTokenizer, but still without success.

This is what I want to do, shown in Python:

for token in re.finditer( "([A-Z])(\d*)", inputString):
      print token.group(1)
      print token.group(2)

For input "A12R5F28" the result would be:

A

12

R

5

F

28
like image 751
Tomas Novotny Avatar asked Sep 19 '10 07:09

Tomas Novotny


1 Answers

You could use regex API in Java and achieve the same functionality:

Pattern myPattern = Pattern.compile("([A-Z])(\d+)")
Matcher myMatcher = myPattern.matcher("A12R5F28");
while (myMatcher.find()) {
      // Do your stuff here
}
like image 105
rkg Avatar answered Sep 18 '22 07:09

rkg