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Marshall map to XML in Go

I'm trying to output a map as XML data, however I receive the following error:

xml: unsupported type: map[string]int

Marshalling maps works fine for JSON so I don't get why it wouldn't work the same for XML. Is using a Struct really the only way?

like image 998
Adam B Avatar asked Jun 19 '15 02:06

Adam B


2 Answers

I ended up solving this by using the xml.Marshaler as suggested by Dave C

// StringMap is a map[string]string.
type StringMap map[string]string

// StringMap marshals into XML.
func (s StringMap) MarshalXML(e *xml.Encoder, start xml.StartElement) error {

    tokens := []xml.Token{start}

    for key, value := range s {
        t := xml.StartElement{Name: xml.Name{"", key}}
        tokens = append(tokens, t, xml.CharData(value), xml.EndElement{t.Name})
    }

    tokens = append(tokens, xml.EndElement{start.Name})

    for _, t := range tokens {
        err := e.EncodeToken(t)
        if err != nil {
            return err
        }
    }

    // flush to ensure tokens are written
    return e.Flush()
}

Source: https://gist.github.com/jackspirou/4477e37d1f1c043806e0

Now the map can be marshalled by simply calling

output, err := xml.MarshalIndent(data, "", "  ")
like image 149
Adam B Avatar answered Oct 27 '22 09:10

Adam B


You can marshal and unmarshal a map, but you need to write the custom MarshalXML and UnmarshalXML function for your map and give you map a type to attach those functions to.

Here's an example that marshals and unmarshals where the key and the value in the map is a string. You can simply change the marshal of the value to int => string and back in the unmarshal: https://play.golang.org/p/4Z2C-GF0E7

package main

import (
    "encoding/xml"
    "fmt"
    "io"
)

type Map map[string]string

type xmlMapEntry struct {
    XMLName xml.Name
    Value   string `xml:",chardata"`
}

// MarshalXML marshals the map to XML, with each key in the map being a
// tag and it's corresponding value being it's contents.
func (m Map) MarshalXML(e *xml.Encoder, start xml.StartElement) error {
    if len(m) == 0 {
        return nil
    }

    err := e.EncodeToken(start)
    if err != nil {
        return err
    }

    for k, v := range m {
        e.Encode(xmlMapEntry{XMLName: xml.Name{Local: k}, Value: v})
    }

    return e.EncodeToken(start.End())
}

// UnmarshalXML unmarshals the XML into a map of string to strings,
// creating a key in the map for each tag and setting it's value to the
// tags contents.
//
// The fact this function is on the pointer of Map is important, so that
// if m is nil it can be initialized, which is often the case if m is
// nested in another xml structurel. This is also why the first thing done
// on the first line is initialize it.
func (m *Map) UnmarshalXML(d *xml.Decoder, start xml.StartElement) error {
    *m = Map{}
    for {
        var e xmlMapEntry

        err := d.Decode(&e)
        if err == io.EOF {
            break
        } else if err != nil {
            return err
        }

        (*m)[e.XMLName.Local] = e.Value
    }
    return nil
}

func main() {
    // The Map
    m := map[string]string{
        "key_1": "Value One",
        "key_2": "Value Two",
    }
    fmt.Println(m)

    // Encode to XML
    x, _ := xml.MarshalIndent(Map(m), "", "  ")
    fmt.Println(string(x))

    // Decode back from XML
    var rm map[string]string
    xml.Unmarshal(x, (*Map)(&rm))
    fmt.Println(rm)
}
like image 23
Leigh McCulloch Avatar answered Oct 27 '22 10:10

Leigh McCulloch