I'm trying to use MapViewOfFile in a 64 bit process on a file that is already mapped to memory of another 32 bit process. It fails and gives me an "access denied" error. Is this a known Windows limitation or am I doing something wrong? Same code works fine with 2 32bit processes.
The code sort of looks like this:
hMapFile = OpenFileMapping(FILE_MAP_ALL_ACCESS, FALSE, szShmName);
if (NULL == hMapFile)
{ /* failed to open - create new (this happens in the 32 bit app) */
SECURITY_ATTRIBUTES sa;
sa.nLength = sizeof(SECURITY_ATTRIBUTES);
sa.bInheritHandle = FALSE;
/* give access to members of administrators group */
BOOL success = ConvertStringSecurityDescriptorToSecurityDescriptor(
"D:(A;OICI;GA;;;BA)",
SDDL_REVISION_1,
&(sa.lpSecurityDescriptor),
NULL);
HANDLE hShmFile = CreateFile(FILE_XXX_SHM,
FILE_ALL_ACCESS, 0,
&sa,
OPEN_ALWAYS, 0, NULL);
hMapFile = CreateFileMapping(hShmFile, &sa, PAGE_READWRITE,
0,
SHM_SIZE,
szShmName);
CloseHandle(hShmFile);
}
// this one fails in 64 bit app
pShm = MapViewOfFile(hMapFile, FILE_MAP_ALL_ACCESS, 0, 0, SHM_SIZE);
When you call CreateFile in the 32-bit application, you're passing 0
for the sharing parameter, which means no sharing is allowed. Changing that to FILE_SHARE_READ | FiLE_SHARE_WRITE
would probably be a step in the right direction.
Edit: I just whipped together a demo that works (at least for me):
#include <windows.h>
#include <iostream>
static const char map_name[] = "FileMapping1";
static const char event1_name[] = "EventName1";
static const char event2_name[] = "EventName2";
int main() {
HANDLE mapping = OpenFileMapping(FILE_MAP_ALL_ACCESS, FALSE, map_name);
if (NULL == mapping) {
std::cout << "Calling CreateFile\n";
HANDLE file = CreateFile("MappedFile",
FILE_ALL_ACCESS,
FILE_SHARE_READ | FILE_SHARE_WRITE,
NULL,
OPEN_ALWAYS,
0,
NULL);
std::cout << "Creating File mapping\n";
mapping = CreateFileMapping(file, NULL, PAGE_READWRITE, 0, 65536, map_name);
std::cout << "Closing file handle\n";
CloseHandle(file);
}
std::cout << "Mapping view of file\n";
char *memory = (char *)MapViewOfFile(mapping, FILE_MAP_ALL_ACCESS, 0, 0, 65536);
if (memory == NULL) {
std::cerr << "Mapping Failed.\n";
return 1;
}
std::cout << "Mapping succeeded\n";
HANDLE event = CreateEvent(NULL, false, false, event1_name);
if (GetLastError()==ERROR_ALREADY_EXISTS) {
std::cout <<"Waiting to receive string:\n";
WaitForSingleObject(event, INFINITE);
std::cout << "Received: " << memory;
HANDLE event2 = CreateEvent(NULL, false, false, event2_name);
SetEvent(event2);
}
else {
char string[] = "This is the shared string";
std::cout << "Sending string: " << string << "\n";
strncpy(memory, string, sizeof(string));
SetEvent(event);
HANDLE event2 = CreateEvent(NULL, false, false, event2_name);
WaitForSingleObject(event2, INFINITE);
}
return 0;
}
Any combination of 32- or 64-bit executables seems to work fine.
Edit2: Note, however, that this is purely demo-level code. Just for example, the name of each shared object should normally contain a GUID-string to ensure against accidental collision with other programs. I've also skipped quite a bit of error checking, not to mention the minor detail that this code doesn't accomplish anything useful.
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