Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Mapping XML to classes in c#

I'm looking to map multiple XML attributes in nested elements into a single POCO class using the XmlSerializer object.

XML

<products grand-total="100">
    <one price="50" />
    <two price="20" />
    <tree price="30" />
</products>

POCO

public class Product
{
    public int GrandTotal { get; set; }
    public int OnePrice { get; set; }
    public int TwoPrice { get; set; }
    public int ThreePrice { get; set; }
}

C#

var doc = XDocument.Load("XmlDoc.xml");
var serializer = new XmlSerializer(typeof(Product));
var reader = doc.Root.CreateReader();
var temp = (Product)serializer.Deserialize(reader);

It would be awesome if anyone knows how I can do this.

Thanks.

like image 784
Jay Avatar asked Mar 16 '15 19:03

Jay


1 Answers

If you're locked into this XML schema, this will serialize or de-serialize your XML and object data:

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class ProductsViewModel
{
    public string Xml { get; set; }

    public Product Poco { get; set; }

    public ProductsViewModel()
    {
        Xml = Serialize(new Product());

        Poco = (Product)Deserialize(Xml, typeof(Product));
    }

    public class Price
    {
        [XmlAttribute(AttributeName = "price")]
        public int Value { get; set; }
    }

    [XmlRoot(ElementName = "products")]
    public class Product
    {
        [XmlAttribute(AttributeName = "grand-total")]
        public int GrandTotal { get; set; }

        [XmlElement(ElementName = "one")]
        public Price OnePrice { get; set; }

        [XmlElement(ElementName = "two")]
        public Price TwoPrice { get; set; }

        [XmlElement(ElementName = "tree")]
        public Price ThreePrice { get; set; }

        public Product()
        {
            GrandTotal = 100;
            OnePrice = new Price { Value = 50 };
            TwoPrice = new Price { Value = 20 };
            ThreePrice = new Price { Value = 30 };
        }
    }

    private string Serialize(object obj)
    {
        var serializer = new XmlSerializer(obj.GetType());

        using (var stringWriter = new StringWriter())
        {
            serializer.Serialize(stringWriter, obj);
            return stringWriter.ToString();
        }
    }

    private object Deserialize(string serializedObj, Type type)
    {
        var serializer = new XmlSerializer(type);

        using (var stringReader = new StringReader(serializedObj))
        using (var xmlTextReader = new XmlTextReader(stringReader))
        {
            return serializer.Deserialize(xmlTextReader);
        }
    }
}
like image 200
JonH Avatar answered Oct 01 '22 20:10

JonH