I have a page where I am trying to parse following json string using JSON.parse
'[{"Name":"Eggs","Complete":false,"Notes":"Notes here\n"},{"Name":"Sugar","Complete":false,"Notes":null}]'
But following code gives error "Uncaught SyntaxError: Unexpected token"
var groceriesJson = JSON.parse(jsonString);
Then I came to know that its because of \n
in json string. So I did try this solution. But no luck. Still same error "Uncaught SyntaxError: Unexpected token"
function escapeSpecialChars(jsonString) {
return jsonString.replace(/\\n/g, "\\n")
.replace(/\\'/g, "\\'")
.replace(/\\"/g, '\\"')
.replace(/\\&/g, "\\&")
.replace(/\\r/g, "\\r")
.replace(/\\t/g, "\\t")
.replace(/\\b/g, "\\b")
.replace(/\\f/g, "\\f");
}
var groceriesJson = JSON.parse(escapeSpecialChars(jsonString));
Any ideas? Thanks
---UPDATE----
I am not creating this string manually, I have c# codes that creates json string from c# objects
var jss = new System.Web.Script.Serialization.JavaScriptSerializer();
var groceries = jss.Serialize(Model);
then in javascript codes I have
var jsonString = '@Html.Raw(groceries)'
var groceriesJson = JSON.parse(escapeSpecialChars(jsonString));
JSON strings do not allow real newlines in its data; it can only have escaped newlines. Snowflake allows escaping the newline character by the use of an additional backslash character.
In JSON object make sure that you are having a sentence where you need to print in different lines. Now in-order to print the statements in different lines we need to use '\\n' (backward slash). As we now know the technique to print in newlines, now just add '\\n' wherever you want.
In JSON the only characters you must escape are \, ", and control codes.
You should just escape the \
as in \\n
, your JSON becoming :
'[{"Name":"Eggs","Complete":false,"Notes":"Notes here\\n"},{"Name":"Sugar","Complete":false,"Notes":null}]';
If you cannot have access to the JSON, then your function should be :
function escapeSpecialChars(jsonString) {
return jsonString.replace(/\n/g, "\\n")
.replace(/\r/g, "\\r")
.replace(/\t/g, "\\t")
.replace(/\f/g, "\\f");
}
var groceriesJson = JSON.parse(escapeSpecialChars(jsonString));
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