Map and filter an array at the same time

Question

You should use Array.reduce for this.

var options = [
  { name: 'One', assigned: true }, 
  { name: 'Two', assigned: false }, 
  { name: 'Three', assigned: true }, 
];

var reduced = options.reduce(function(filtered, option) {
  if (option.assigned) {
     var someNewValue = { name: option.name, newProperty: 'Foo' }
     filtered.push(someNewValue);
  }
  return filtered;
}, []);

document.getElementById('output').innerHTML = JSON.stringify(reduced);

<h1>Only assigned options</h1>
<pre id="output"> </pre>

---

Alternatively, the reducer can be a pure function, like this

var reduced = options.reduce(function(result, option) {
  if (option.assigned) {
    return result.concat({
      name: option.name,
      newProperty: 'Foo'
    });
  }
  return result;
}, []);

Since 2019, Array.prototype.flatMap is good option.

options.flatMap(o => o.assigned ? [o.name] : []);

---

From the MDN page linked above:

flatMap can be used as a way to add and remove items (modify the number of items) during a map. In other words, it allows you to map many items to many items (by handling each input item separately), rather than always one-to-one. In this sense, it works like the opposite of filter. Simply return a 1-element array to keep the item, a multiple-element array to add items, or a 0-element array to remove the item.

Use reduce, Luke!

function renderOptions(options) {
    return options.reduce(function (res, option) {
        if (!option.assigned) {
            res.push(someNewObject);
        }
        return res;
    }, []);   
}

With ES6 you can do it very short:

options.filter(opt => !opt.assigned).map(opt => someNewObject)

One line reduce with ES6 fancy spread syntax is here!

var options = [
  { name: 'One', assigned: true }, 
  { name: 'Two', assigned: false }, 
  { name: 'Three', assigned: true }, 
];

const filtered = options
  .reduce((result, {name, assigned}) => [...result, ...assigned ? [name] : []], []);

console.log(filtered);

I'd make a comment, but I don't have the required reputation. A small improvement to Maxim Kuzmin's otherwise very good answer to make it more efficient:

const options = [
  { name: 'One', assigned: true }, 
  { name: 'Two', assigned: false }, 
  { name: 'Three', assigned: true }, 
];

const filtered = options
  .reduce((result, { name, assigned }) => assigned ? result.push(name) && result : result, []);

console.log(filtered);

Explanation

Instead of spreading the entire result over and over for each iteration, we only append to the array, and only when there's actually a value to insert.

At some point, isn't it easier(or just as easy) to use a forEach

var options = [
  { name: 'One', assigned: true }, 
  { name: 'Two', assigned: false }, 
  { name: 'Three', assigned: true }, 
];

var reduced = []
options.forEach(function(option) {
  if (option.assigned) {
     var someNewValue = { name: option.name, newProperty: 'Foo' }
     reduced.push(someNewValue);
  }
});

document.getElementById('output').innerHTML = JSON.stringify(reduced);

<h1>Only assigned options</h1>
<pre id="output"> </pre>

However it would be nice if there was a malter() or fap() function that combines the map and filter functions. It would work like a filter, except instead of returning true or false, it would return any object or a null/undefined.