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manipulating LARGE_INTEGERS

Tags:

c++

int64

I am converting some code from C to C++ in MS dev studio under win32. In the old code I was doing some high speed timings using QueryPerformanceCounter() and did a few manipulations on the __int64 values obtained, in particular a minus and a divide. But now under C++ I am forced to use LARGE_INTEGER because that's what QueryPerformanceCounter() returns. But now on the lines where I try and do some simple maths on the values I get an error:

error C2676: binary '-' : 'LARGE_INTEGER' does not define this operator or a conversion to a type acceptable to the predefined operator

I tried to cast the variables to __int64 but then get:

error C2440: 'type cast' : cannot convert from 'LARGE_INTEGER' to '__int64'

How do I resolve this?

Thanks,

like image 780
Mick Avatar asked Sep 08 '09 17:09

Mick


People also ask

What is QuadPart?

If your compiler has built-in support for 64-bit integers, use the QuadPart member to store the 64-bit integer. Otherwise, use the LowPart and HighPart members to store the 64-bit integer. So if your compiler supports 64 bit integers use quadPart like this : LARGE_INTEGER a, b; __int64 diff = a.QuadPart - b.QuadPart.

What is __ int64?

The __int64 type, for instance, always has the size 64 bits both on the 32-bit and 64-bit platforms. The types size_t and ptrdiff_t are 32-bit on the 32-bit platform and 64-bit on the 64-bit platform. It is this point that causes troubles and confusion when printing values of these types.


5 Answers

LARGE_INTEGER is a union of a 64-bit integer and a pair of 32-bit integers. If you want to perform 64-bit arithmetic on one you need to select the 64-bit int from inside the union.

LARGE_INTEGER a = { 0 };
LARGE_INTEGER b = { 0 };

__int64 c = a.QuadPart - b.QuadPart;
like image 189
Jorge Ferreira Avatar answered Oct 05 '22 09:10

Jorge Ferreira


LARGE_INTEGER is a union, documented here. You probably want a QuadPart member.

like image 40
Cat Plus Plus Avatar answered Oct 05 '22 11:10

Cat Plus Plus


Here it is:

LARGE_INTEGER x,y;
///
//Some codes...
///

__int64 diff = x.QuadPart - y.QuadPart

Because QuadPart is defined as a LONGLONG , that same as __int64.

like image 35
Isaac Avatar answered Oct 05 '22 10:10

Isaac


LARGE_INTEGER is a union, you can still use .QuadPart if you want to work on the 64-bit value.

like image 27
jcopenha Avatar answered Oct 05 '22 09:10

jcopenha


As the Documentation says in the Remarks section :

The LARGE_INTEGER structure is actually a union. If your compiler has built-in support for 64-bit integers, use the QuadPart member to store the 64-bit integer. Otherwise, use the LowPart and HighPart members to store the 64-bit integer.

So if your compiler supports 64 bit integers use quadPart like this :

LARGE_INTEGER a, b;
__int64 diff = a.QuadPart - b.QuadPart
like image 44
Mehdi Ijadnazar Avatar answered Oct 05 '22 11:10

Mehdi Ijadnazar