make shared_ptr not use delete

Question

Or how about using the stl to provide the wrapper functor - Doug T. description but without the custom caller.

boost::shared_ptr<T> ptr( new T, std::mem_fun_ref(&T::deleteMe) );
boost::shared_ptr<S> ptr( new S, std::ptr_fun(lib_freeXYZ) );

You can give the shared_ptr template a custom deleter function which has the signature

  void Deleter( T* ptr);

for a boost::shared_ptr

So for Deleter you would do

  boost::shared_ptr<T> ptrToT( new T, Deleter );

then in the body of Deleter:

   void Deleter( T* ptr);
   {
        ptr->deleteMe();
        // And make sure YOU ACTUALLY DELETE (or do whatever else you need to
        // do to release the resource)
        delete ptr;
   }

For your specific case when you need something simple (like ptr->deleteMe) see Greg's solution, its very nice.

Doug T. answered your question nicely. I'll tell you about intrusive_ptr. Maybe you can use it in your project too.

If you have some C library that has already reference counting, but you have to manually call those functions, you can use boost::intrusive_ptr too, and provide proper definitions for its add_ref and release functions. intrusive_ptr will find and call them. They are responsible to increment the reference count and decrement it, freeing the resource when necassary:

void intrusive_ptr_add_ref(foo *f) {
    lib_add_ref(f);
}

void intrusive_ptr_release(foo *f) {
    if(lib_dec_ref(f) == 0) 
        lib_free(f);
}

Then you can just create objects from raw pointers of type foo*. intrusive_ptr will call your functions when its copied/destructed:

intrusive_ptr<foo> f(lib_alloc());

// can wrap raw pointers too, which already may be referenced somewhere else
foo *p = get_foo_from_somewhere();
function_taking_intrusive_ptr(p);

For the C-style data, do as @Doug. T suggested.

For your class, why not do cleanup in a destructor? Even if this is including deleteMe() in the destructor.