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load spring bean into a servlet

There are many documentations out there on how to achieve this task but I still couldn't resolve my issue. I'm new to working with servlet so I probably missed something.

I use red5 that uses tomcat 6 to create a servlet that uses a spring bean that's of a MysqlDb class for database manipulations.

when I point to red5 using port 5080 it acts as a regular tomcat server and i can browse jsp and servlet pages.

my web.xml contains the following relevant information:

<listener>
 <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<servlet>
  <servlet-name>fbauth</servlet-name>
  <servlet-class>com.xpogames.FbAuth</servlet-class>
</servlet>

<servlet-mapping>
  <servlet-name>fbauth</servlet-name>
  <url-pattern>/fbauth</url-pattern>
</servlet-mapping>

my applicationContext.xml:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">

<bean id="placeholderConfig" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
    <property name="location" value="/WEB-INF/red5-web.properties" />
</bean>

<bean id="idDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
    <property name="driverClassName"><value>${db.driver}</value></property>
    <property name="url"><value>${db.url}</value></property>
    <property name="username"><value>${db.username}</value></property>
    <property name="password"><value>${db.password}</value></property>
    <property name="poolPreparedStatements"><value>true</value></property>
    <property name="maxActive"><value>10</value></property>
    <property name="maxIdle"><value>10</value></property>
 </bean>
 
 <bean id="MysqlDb" class="com.xpogames.MysqlDb">
    <property name="idDataSource" ref="idDataSource"/>
 </bean>
 

</beans>

my FbAuth servlet:

package com.xpogames;

import java.io.IOException;

import java.io.PrintWriter;


import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.beans.factory.BeanFactory;
import org.springframework.context.ApplicationContext;
import org.springframework.web.context.WebApplicationContext;
import org.springframework.web.context.support.WebApplicationContextUtils;

public class FbAuth extends HttpServlet {
private static final long serialVersionUID = 1L;
   
public FbAuth() {
    super();
    // TODO Auto-generated constructor stub
}

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    PrintWriter out = response.getWriter();
    WebApplicationContext webApplicationContext = WebApplicationContextUtils.getRequiredWebApplicationContext(request.getSession().getServletContext());
    MysqlDb mysqlDb = (MysqlDb)webApplicationContext.getBean("MysqlDb");
    out.println(mysqlDb.testme());
    out.println("Hello, world!");
    out.close();        
}

}

I get the following error:

java.lang.IllegalStateException: Context attribute is not of type WebApplicationContext

I think I'm not fetching the spring bean correctly.

any ideas?

thank you!

update

this is my new init function:

public void init(ServletConfig config) throws ServletException {
    super.init(config);
     ServletContext servletContext = this.getServletContext();
    this._context = WebApplicationContextUtils.getRequiredWebApplicationContext(servletContext);
}

thanks a lot! :)

like image 640
ufk Avatar asked Jun 20 '11 16:06

ufk


1 Answers

I use the following in the init() method of the servlet. The init() method is called only once in a Servlets lifecycle.

ApplicationContext context = 
    WebApplicationContextUtils.getRequiredWebApplicationContext(
        this.getServletContext());

Also, do you have the "contextConfigLocation" in your web.xml?

<context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:/**/spring-config.xml
        </param-value>
 </context-param>
like image 96
Rajendra Avatar answered Oct 24 '22 10:10

Rajendra