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I'm working with Ruby 1.8 and I have script that I want to call but it's in a parent folder. Below is the structure:
maindir/
neededscript.rb
subdir/
subdir2/
myscript.rb
How can I require neededscript.rb from inside myscript.rb?
884
To change directories using absolute pathnames, type cd /directory/directory; to change directories using relative pathnames, type cd directory to move one directory below, cd directory/directory to move two directories below, etc.; to jump from anywhere on the filesystem to your login directory, type cd; to change to ...
Directory: A named group of files (a folder); a directory that contains more folders (subdirectories) are called the "parent" and the folder within it is referred to as the "child" of that directory..
How do I open a file in a different directory in Python? Use open() to open a file in a different directory Join path with filename into a path to filename from the current directory. Call open(file) with file as the resultant path to filename to open filename from the current directory.
In Ruby >=1.9 you can use the require_relative method
require_relative complements the builtin method require by allowing you to load a file that is relative to the file containing the require_relative statement.
require_relative '../../neededscript.rb'
You can also add the path to the ruby libs path by adding these lines to myscript.rb before doing the require
binpath = File.dirname( __FILE__ )
$:.unshift File.expand_path( File.join( binpath, ".." ) )
This is what I've done instead:
File.expand_path("../../neededsript.rb",File.dirname(__FILE__))
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