List Directories and get the name of the Directory

Question

I am trying to get the code to list all the directories in a folder, change directory into that folder and get the name of the current folder. The code I have so far is below and isn't working at the minute. I seem to be getting the parent folder name.

import os  for directories in os.listdir(os.getcwd()):      dir = os.path.join('/home/user/workspace', directories)     os.chdir(dir)     current = os.path.dirname(dir)     new = str(current).split("-")[0]     print new 

I also have other files in the folder but I do not want to list them. I have tried the below code but I haven't got it working yet either.

for directories in os.path.isdir(os.listdir(os.getcwd())):  

Can anyone see where I am going wrong?

Thanks

Got it working but it seems a bit round about.

import os os.chdir('/home/user/workspace') all_subdirs = [d for d in os.listdir('.') if os.path.isdir(d)] for dirs in all_subdirs:     dir = os.path.join('/home/user/workspace', dirs)     os.chdir(dir)     current = os.getcwd()     new = str(current).split("/")[4]     print new 

Answer 1

This will print all the subdirectories of the current directory:

print [name for name in os.listdir(".") if os.path.isdir(name)] 

I'm not sure what you're doing with split("-"), but perhaps this code will help you find a solution?

If you want the full pathnames of the directories, use abspath:

print [os.path.abspath(name) for name in os.listdir(".") if os.path.isdir(name)] 

Note that these pieces of code will only get the immediate subdirectories. If you want sub-sub-directories and so on, you should use walk as others have suggested.

Answer 2

import os for root, dirs, files in os.walk(top, topdown=False):     for name in dirs:         print os.path.join(root, name) 

Walk is a good built-in for what you are doing