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LINQ query to select top five

Tags:

c#

linq

People also ask

How do I get the top 1 record in Linq?

Use the OrderByDesecnding() amd First() query operators. No - LINQ to SQL does the optimization of doing everything on the server side and getting you only one record. Great! That works, it produces a nice "select top 1" T-SQL.

How do I select a query in Linq?

LINQ query syntax always ends with a Select or Group clause. The Select clause is used to shape the data. You can select the whole object as it is or only some properties of it. In the above example, we selected the each resulted string elements.


var list = (from t in ctn.Items
           where t.DeliverySelection == true && t.Delivery.SentForDelivery == null
           orderby t.Delivery.SubmissionDate
           select t).Take(5);

The solution:

var list = (from t in ctn.Items
           where t.DeliverySelection == true && t.Delivery.SentForDelivery == null
           orderby t.Delivery.SubmissionDate
           select t).Take(5);

This can also be achieved using the Lambda based approach of Linq;

var list = ctn.Items
.Where(t=> t.DeliverySelection == true && t.Delivery.SentForDelivery == null)
.OrderBy(t => t.Delivery.SubmissionDate)
.Take(5);

[Offering a somewhat more descriptive answer than the answer provided by @Ajni.]

This can also be achieved using LINQ fluent syntax:

var list = ctn.Items
    .Where(t=> t.DeliverySelection == true && t.Delivery.SentForDelivery == null)
    .OrderBy(t => t.Delivery.SubmissionDate)
    .Take(5);

Note that each method (Where, OrderBy, Take) that appears in this LINQ statement takes a lambda expression as an argument. Also note that the documentation for Enumerable.Take begins with:

Returns a specified number of contiguous elements from the start of a sequence.


Additional information

Sometimes it is necessary to bind a model into a view models and give a type conversion error. In this situation you should use ToList() method.

var list = (from t in ctn.Items
       where t.DeliverySelection == true && t.Delivery.SentForDelivery == null
       orderby t.Delivery.SubmissionDate
       select t).Take(5).ToList();