Laravel Multiple Middleware in Route with OR Condition

Question

I wonder if I can do this in Laravel Route. Let's say I have Admin, Premium and User (which can be login too by using Auth) Middleware. Also, I have controller with methods like this: index, create, edit, delete and I want Admin to be able do all those things, but Premium can only be able to access index method, and User can't access anything in this controller (he can access another controller). I know I can use except or only middleware method like this:

    public function __construct()
    {
    $this->middleware('premium')->only('index');
    $this->middleware('admin'); 
    // or maybe $this->middleware('admin')->except('index');
    }

but when I try to put these two middlewares in __construct method they will start to conflict each other, it makes sense because index method can be access by Premium Member but then can't be access by the Admin itself. Btw my middleware is simply checking:

    if (Auth::check()) {
        if (Auth::user()->role == 'Admin') {
            return $next($request);
        }
     }
    return redirect('/home');

So, back to my question, can I have OR Middleware so I can avoid conflict from multiple middleware (which is must be AND condition when they written at the same controller constructor)?

Thanks a lot.

Answer 1

If you change up the way your logic is thinking a little bit, the answer becomes pretty easy. You can create new middleware that checks if it can access the specific method.

So create the following middleware 'CanAccessIndex':

if (Auth::check()) {
    if (Auth::user()->role == 'Admin' || Auth::user()->role == 'Premium') {
        return $next($request);
    }
 }
return redirect('/home');

Then, you can put that middleware on the index function (instead of the premium middleware) and put your admin middleware on everything EXCEPT index. Like so:

public function __construct()
{
    $this->middleware('canAccessIndex')->only('index');
    $this->middleware('admin')->except('index');
}

That's one way to do it.