I have some route/model binding set up in my project for one of my models, and that works just fine. I'm able to use my binding in my route path and accept an instance of my model as a parameter to the relevant method in my controller.
Now I'm trying to do some work with this model, so I have created a method in my controller that accepts a Form Request so I can carry out some validation.
public function edit(EditBrandRequest $request, Brand $brand) { // ...
Each different instance of my model can be validated differently, so I need to be able to use an instance of the model in order to build a custom set of validation rules.
Is there a way of getting the instance of the model, that is injected into the controller from the Form Request?
I have tried type-hinting the model instance in the Form Request's constructor
class EditBrandRequest extends Request { public function __construct(Brand $brand) { dd($brand); }
I have also tried type-hinting the model instance in the Form Request's rules()
method.
class EditBrandRequest extends Request { // ... public function rules(Brand $brand) { dd($brand);
In both instances I am provided an empty/new instance of the model, rather than the instance I am expecting.
Of course, I could always get around this by not bothering with Form Requests and just generate the rules in the controller and validate manually - but I would rather do it the Laravel way if it's possible.
Thanks
Laravel route model binding provides a convenient way to automatically inject the model instances directly into your routes. For example, instead of injecting a user's ID, you can inject the entire User model instance that matches the given ID.
Laravel currently supports two types of route model bindings. We have: Implicit model binding. explicit model binding.
Implicit Binding Laravel will then automatically inject the model instance that has an id field matching the corresponding value from the request URI. If a matching model instance is not found in the database, a 404 HTTP response will automatically be generated for that particular route.
You can simply access it using the binding key, so for example if you bind Brand
model: $router->model('brand', '\App\Brand')
you can get instance of your model with $this->brand
. Here is validation rules example:
'slug' => 'required|unique:brand,slug,' . $this->brand->id,
EDIT
Sometimes you might have an input name that uses the same name as the binding key, for example, if you bind Address
model as address
then you have an input field address
it will make Laravel confuse. For this situation you can use route()
method.
'address' => 'required|unique:addresses,address,' . $this->route('address')->id,
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