PHP using preg_replace : "Delimiter must not be alphanumeric or backslash" error

Question

I am trying to take a string of text like so:

$string = "This (1) is (2) my (3) example (4) text"; 

In every instance where there is a positive integer inside of parentheses, I'd like to replace that with simply the integer itself.

The code I'm using now is:

$result = preg_replace("\((\d+)\)", "$0", $string); 

But I keep getting a

Delimiter must not be alphanumeric or backslash.

Warning

Any thoughts? I know there are other questions on here that sort of answer the question, but my knowledge of regex is not enough to switch it over to this example.

Answer 1

You are almost there. You are using:

$result = preg_replace("((\d+))", "$0", $string); 

• The regex you specify as the 1st argument to preg_* family of function should be delimited in pair of delimiters. Since you are not using any delimiters you get that error.
• ( and ) are meta char in a regex, meaning they have special meaning. Since you want to match literal open parenthesis and close parenthesis, you need to escape them using a \. Anything following \ is treated literally.
• You can capturing the integer correctly using \d+. But the captured integer will be in $1 and not $0. $0 will have the entire match, that is integer within parenthesis.

If you do all the above changes you'll get:

$result = preg_replace("#\((\d+)\)#", "$1", $string);