Kotlin: get list of all files in resource folder

Question

Is there a way to get list of all files in "resources" folder in Kotlin?

I can read specific file as

Application::class.java.getResourceAsStream("/folder/filename.ext")

But sometimes I just want to extract everything from folder "folder" to an external directory.

Answer 1

As I struggled with the same issue and couldn't find a concrete answer, so I had to write one myself.

Here is my solution:

fun getAllFilesInResources()
{
    val projectDirAbsolutePath = Paths.get("").toAbsolutePath().toString()
    val resourcesPath = Paths.get(projectDirAbsolutePath, "/src/main/resources")
    val paths = Files.walk(resourcesPath)
                    .filter { item -> Files.isRegularFile(item) }
                    .filter { item -> item.toString().endsWith(".txt") }
                    .forEach { item -> println("filename: $item") }
}

Here I have parsed through all the files in the /src/main/resources folder and then filtered only the regular files (no directories included) and then filtered for the text files within the resources directory.

The output is a list of all the absolute file paths with the extension .txt in the resources folder. Now you can use these paths to copy the files to an external folder.

Answer 2

There are no methods for it (i.e. Application::class.java.listFilesInDirectory("/folder/")), but you can create your own system to list the files in a directory:

@Throws(IOException::class)
fun getResourceFiles(path: String): List<String> = getResourceAsStream(path).use{
    return if(it == null) emptyList()
    else BufferedReader(InputStreamReader(it)).readLines()
}

private fun getResourceAsStream(resource: String): InputStream? = 
        Thread.currentThread().contextClassLoader.getResourceAsStream(resource) 
                ?: resource::class.java.getResourceAsStream(resource)

Then just call getResourceFiles("/folder/") and you'll get a list of files in the folder, assuming it's in the classpath.

This works because Kotlin has an extension function that reads lines into a List of Strings. The declaration is:

/**
 * Reads this reader content as a list of lines.
 *
 * Do not use this function for huge files.
 */
public fun Reader.readLines(): List<String> {
    val result = arrayListOf<String>()
    forEachLine { result.add(it) }
    return result
}

Answer 3

Two distinct parts:

1. Obtain a file that represents the resource directory
2. Traverse the directory

For 1 you can use Java's getResource:

val dir = File( object {}.javaClass.getResource(directoryPath).file )

For 2 you can use Kotlin's File.walk extension function that returns a sequence of files which you can process, e.g:

dir.walk().forEach { f ->
    if(f.isFile) {
        println("file ${f.name}")
    } else {
        println("dir ${f.name}")
    }
}

Put together you may end up with the following code:

fun onEachResource(path: String, action: (File) -> Unit) {

    fun resource2file(path: String): File {
        val resourceURL = object {}.javaClass.getResource(path)
        return File(checkNotNull(resourceURL, { "Path not found: '$path'" }).file)
    }

    with(resource2file(path)) {
        this.walk().forEach { f -> action(f) }
    }
}

so that if you have resources/nested direcory, you can:

fun main() {
    
    val print = { f: File ->
        when (f.isFile) {
            true -> println("[F] ${f.absolutePath}")
            false -> println("[D] ${f.absolutePath}")
        }
    }
    
    onEachResource("/nested", print)
}