Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

JSON.parse error on a seemingly valid JSON [duplicate]

I'm using JSON.parse() to parse a json that's being returned from an api (Laravel 5) called using jquery's $.get(). The json is seemingly valid, however, JSON.parse() is returning error in both Safari and Chrome.

Chrome says:

Uncaught SyntaxError: Unexpected token o

Safari says:

SyntaxError: JSON Parse error: Unexpected identifier "object"

The code fragment is as below:

    $.get('/foo/' + product_id, function(data){
        console.log(data);
        var product = JSON.parse(data);
        if (product) {
            // do something
        }
     });

The JSON is:

{  
   "id":"1b7b3eb7-8769-48fe-a421-64c105de3eff",
   "parent":null,
   "org_id":"845d0d53-de68-42c3-9007-c3d0e72c555e",
   "category_id":"e58237f7-e040-4098-8d46-b84f8cdf7d83",
   "purchase_tax":null,
   "sale_tax":null,
   "code":"982",
   "name":"Mr. Destin Hoppe",
   "is_purchased":false,
   "is_sold":false,
   "purchase_price":null,
   "selling_price":null,
   "purchase_includes_tax":false,
   "sale_includes_tax":false,
   "created_at":"2015-09-16 17:39:34",
   "updated_at":"2015-09-16 17:39:34"
}

Interestingly, eval() works just fine.

like image 268
Code Poet Avatar asked Sep 17 '15 16:09

Code Poet


1 Answers

The error is a result of data being an object, not JSON. You don't need to parse anything; it is already a JavaScript object. jQuery does the parsing within its get method. To confirm this, add this line to the top of the callback.

console.log(data["id"]);

As another example of this error, the following line will also fail for the same reason.

JSON.parse({});
like image 119
Drew Gaynor Avatar answered Sep 20 '22 02:09

Drew Gaynor