I'm using JSON for data interchange. And I'm using JSON.NET framework.
I have the class:
public class CarEntity
{
public string Model { get; set; }
public int Year { get; set; }
public int Price { get; set; }
}
And I have following code:
public void Test()
{
var jsonString =
@"{
""Model"": ""Dodge Caliber"",
""Year"": 2011,
""Price"": 15000,
""Mileage"": 35000
}";
var parsed = (CarEntity)JsonConvert.DeserializeObject(jsonString, typeof(CarEntity));
}
Since there are no "Mileage" field in CarEntity class I need log warning about it:
Unknown field: Mileage=35000
Is there some way to do it?
It is little tricky but you can. Change your code to:
var parsed = (CarEntity)JsonConvert.DeserializeObject(jsonString, typeof(CarEntity), new JsonSerializerSettings()
{
MissingMemberHandling = MissingMemberHandling.Error,
Error = ErrorHandler
});
And add:
private static void ErrorHandler(object x, ErrorEventArgs error)
{
Console.WriteLine(error.ErrorContext.Error);
error.ErrorContext.Handled = true;
}
You should probably do more with the last line, because now every error will not throw an exception.
UPDATE
Decompiled code form invoking exception in Json.NET:
if (this.TraceWriter != null && this.TraceWriter.LevelFilter >= TraceLevel.Verbose)
this.TraceWriter.Trace(TraceLevel.Verbose, JsonPosition.FormatMessage(reader as IJsonLineInfo, reader.Path, StringUtils.FormatWith("Could not find member '{0}' on {1}", (IFormatProvider) CultureInfo.InvariantCulture, (object) propertyName, (object) contract.UnderlyingType)), (Exception) null);
if (this.Serializer.MissingMemberHandling == MissingMemberHandling.Error)
throw JsonSerializationException.Create(reader, StringUtils.FormatWith("Could not find member '{0}' on object of type '{1}'", (IFormatProvider) CultureInfo.InvariantCulture, (object) propertyName, (object) contract.UnderlyingType.Name));
reader.Skip();
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