I'm deserializing an object using Json.NET
that contains a private field of type Guid and a public property for that field. When the value for my Guid
is null in my json I want to assign Guid.Empty
to my field.
public class MyClass
{
private Guid property;
public Guid Property
{
get { return property; }
set
{
if (value == null)
{
property = Guid.Empty;
}
else
{
property = value;
}
}
}
}
But the deserializer
wants to access the private field, cause I get this error when I try to deserialize:
Error converting value {null} to type 'System.Guid'. Path '[0].property', line 6, position 26.
How can I make it ignore the private field and use the public property instead?
Json.NET refuses to set a null
value for a Guid
because it is a non-nullable value type. Try typing (Guid)null
in the Immediate Window and you will see an error message indicating that this conversion cannot be made in .Net.
To work around this, you have a couple of options:
Create a Guid?
nullable proxy property. It can be private if you desire as long as it has a [JsonProperty]
attribute:
public class MyClass
{
[JsonIgnore]
public Guid Property { get; set; }
[JsonProperty("Property")]
Guid? NullableProperty { get { return Property == Guid.Empty ? null : (Guid?)Property; } set { Property = (value == null ? Guid.Empty : value.Value); } }
}
Create a JsonConverter
that converts a null
Json token to a default Guid value:
public class NullToDefaultConverter<T> : JsonConverter where T : struct
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(T);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
var token = JToken.Load(reader);
if (token == null || token.Type == JTokenType.Null)
return default(T);
return token.ToObject(objectType); // Deserialize using default serializer
}
// Return false instead if you don't want default values to be written as null
public override bool CanWrite { get { return true; } }
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
if (EqualityComparer<T>.Default.Equals((T)value, default(T)))
writer.WriteNull();
else
writer.WriteValue(value);
}
}
Then apply it to your type as follows:
public class MyClass
{
[JsonConverter(typeof(NullToDefaultConverter<Guid>))]
public Guid Property { get; set; }
}
Alternatively, you can apply the converter to all values of type T
by adding the converter to JsonSerializerSettings.Converters
. And, to register such a converter globally, see e.g.How to set custom JsonSerializerSettings for Json.NET in MVC 4 Web API? for Web API, Setting JsonConvert.DefaultSettings asp net core 2.0 not working as expected for ASP.NET Core or Registering a custom JsonConverter globally in Json.Net for a console app.
If you do register the converter globally for a console app, you may need to disable it for recursive calls as shown in JSON.Net throws StackOverflowException when using [JsonConvert()].
If you only need to deserialize a null
value for a Guid and not re-serialize it as such, you can apply [JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
to the Guid property, and null
values will ignored despite being invalid Guid values:
public class MyClass
{
[JsonProperty(NullValueHandling = NullValueHandling.Ignore)]
public Guid Property { get; set; }
}
Of course if you do this your Guid will be re-serialized as "00000000-0000-0000-0000-000000000000"
. To ameliorate that you could apply DefaultValueHandling = DefaultValueHandling.Ignore
which will cause empty Guid values to be omitted during serialization:
[JsonProperty(NullValueHandling = NullValueHandling.Ignore, DefaultValueHandling = DefaultValueHandling.Ignore)]
public Guid Property { get; set; }
Note that if a parameterized constructor called during deserialization has a non-nullable Guid argument with the same name, a different approach may be required.
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