I am posting some data into the database using Volley and I get the following jsonarray response.
[
{
"nickname":"panikos",
"username":"[email protected]",
"user_type":"LEADER",
"latest_steps":"0"
}
]
This is a sample of my code that unfortunately doesn't log out or debug the variable of "nickname" object:(.
final JsonArrayRequest jsonObjReq1 = new
JsonArrayRequest(AppConfig.URL_GET_TEAM, jsonObject,
new com.android.volley.Response.Listener<JSONArray>() {
@Override
public void onResponse(JSONArray response) {
Log.d("TAG", response.toString());
try {
JSONArray jsonArray = new JSONArray(response);
for(int i=0;i<jsonArray.length();i++){
JSONObject jresponse =
jsonArray.getJSONObject(i);
String nickname =
jresponse.getString("nickname");
Log.d("nickname",nickname);
}
} catch (JSONException e) {
e.printStackTrace();
}
//pDialog.dismiss();
}
}, new com.android.volley.Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.d("TAG", "Error: " + error.getMessage());
//pDialog.dismiss();
}
}) {
@Override
public String getBodyContentType() {
return "application/json; charset=utf-8";
}
};
Any ideas? Am I missing something?
Thanks.
JsonArray represents an immutable JSON array (an ordered sequence of zero or more values). It also provides an unmodifiable list view of the values in the array. A JsonArray object can be created by reading JSON data from an input source or it can be built from scratch using an array builder object.
JSON (Javascript Object Notation) is a programming language . It is minimal, textual, and a subset of JavaScript. It is an alternative to XML. Android provides support to parse the JSON object and array.
A JSON array contains zero, one, or more ordered elements, separated by a comma. The JSON array is surrounded by square brackets [ ] . A JSON array is zero terminated, the first index of the array is zero (0). Therefore, the last index of the array is length - 1.
I the problem might be - you are already getting response
as a JSONArray
.
So, you can Call
JSONObject jresponse = response.getJSONObject(0);
and if you have more than 1 object in response, then
for(int i = 0; i < response.length(); i++){
JSONObject jresponse = response.getJSONObject(i);
String nickname = jresponse.getString("nickname");
Log.d("nickname", nickname);
}
Remove this :
try {
JSONArray jsonArray = new JSONArray(response);
for(int i=0;i<jsonArray.length();i++){
JSONObject jresponse =
jsonArray.getJSONObject(i);
String nickname =
jresponse.getString("nickname");
Log.d("nickname",nickname);
}
} catch (JSONException e) {
e.printStackTrace();
}
and add :
try {
JSONObject jresponse = response.getJSONObject(0);
String nickname = jresponse.getString("nickname");
Log.d("nickname",nickname);
}catch (JSONException e) {
e.printStackTrace();
}
The Code looks good, however i think you might be missing a call to add jsonObjReq1
in the request queue. I would suggest to use Singleton Pattern.
Fixed!!!
@Override
public void onResponse(JSONArray response) {
Log.d("TAG", response.toString());
try {
Log.d("JsonArray",response.toString());
for(int i=0;i<response.length();i++){
JSONObject jresponse = response.getJSONObject(i);
String nickname = jresponse.getString("nickname");
Log.d("nickname",nickname);
}
} catch (JSONException e) {
e.printStackTrace();
}
//pDialog.dismiss();
}
There was no need to create a new JSONArray. It was created inside the onResponse() method. The next project I am assigned to do is going to have more complicate webservices.omg!!!
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