What this essentially means is that while having unique keys is recommended, it is not a must. We can have duplicate keys in a JSON object, and it would still be valid. The validity of duplicate keys in JSON is an exception and not a rule, so this becomes a problem when it comes to actual implementations.
The short answer: Yes but is not recommended.
In order to set a key-value pair in a KiiObject, call the set() method of the KiiObject class. The set() method has an overloaded version for each data type. Specify a key-value pair as arguments of the set() method. The specified key-value pair will be saved at the first level of the JSON document hierarchy.
There are two ways to access properties of objects:
var obj = {a: 'foo', b: 'bar'};
obj.a //foo
obj['b'] //bar
Or, if you need to dynamically do it:
var key = 'b';
obj[key] //bar
If you don't already have it as an object, you'll need to convert it.
For a more complex example, let's assume you have an array of objects that represent users:
var users = [{name: 'Corbin', age: 20, favoriteFoods: ['ice cream', 'pizza']},
{name: 'John', age: 25, favoriteFoods: ['ice cream', 'skittle']}];
To access the age property of the second user, you would use users[1].age
. To access the second "favoriteFood" of the first user, you'd use users[0].favoriteFoods[2]
.
Another example: obj[2].key[3]["some key"]
That would access the 3rd element of an array named 2. Then, it would access 'key' in that array, go to the third element of that, and then access the property name some key
.
As Amadan noted, it might be worth also discussing how to loop over different structures.
To loop over an array, you can use a simple for loop:
var arr = ['a', 'b', 'c'],
i;
for (i = 0; i < arr.length; ++i) {
console.log(arr[i]);
}
To loop over an object is a bit more complicated. In the case that you're absolutely positive that the object is a plain object, you can use a plain for (x in obj) { }
loop, but it's a lot safer to add in a hasOwnProperty check. This is necessary in situations where you cannot verify that the object does not have inherited properties. (It also future proofs the code a bit.)
var user = {name: 'Corbin', age: 20, location: 'USA'},
key;
for (key in user) {
if (user.hasOwnProperty(key)) {
console.log(key + " = " + user[key]);
}
}
(Note that I've assumed whatever JS implementation you're using has console.log
. If not, you could use alert
or some kind of DOM manipulation instead.)
Try the JSON Parser by Douglas Crockford at github. You can then simply create a JSON object out of your String variable as shown below:
var JSONText = '{"c":{"a":[{"name":"cable - black","value":2},{"name":"case","value":2}]},"o":{"v":[{"name":"over the ear headphones - white/purple","value":1}]},"l":{"e":[{"name":"lens cleaner","value":1}]},"h":{"d":[{"name":"hdmi cable","value":1},{"name":"hdtv essentials (hdtv cable setup)","value":1},{"name":"hd dvd \u0026 blue-ray disc lens cleaner","value":1}]}'
var JSONObject = JSON.parse(JSONText);
var c = JSONObject["c"];
var o = JSONObject["o"];
Ok, here is the JS code:
var data = JSON.parse('{"c":{"a":{"name":"cable - black","value":2}}}')
for (var event in data) {
var dataCopy = data[event];
for (data in dataCopy) {
var mainData = dataCopy[data];
for (key in mainData) {
if (key.match(/name|value/)) {
alert('key : ' + key + ':: value : ' + mainData[key])
}
}
}
}
FIDDLE HERE
var yourobj={
"c":{
"a":[{"name":"cable - black","value":2},{"name":"case","value":2}]
},
"o":{
"v":[{"name":"over the ear headphones - white/purple","value":1}]
},
"l":{
"e":[{"name":"lens cleaner","value":1}]
},
"h":{
"d":[{"name":"hdmi cable","value":1},
{"name":"hdtv essentials (hdtv cable setup)","value":1},
{"name":"hd dvd \u0026 blue-ray disc lens cleaner","value":1}]
}}
my solution
var obj = [];
for(n1 in yourjson)
for(n1_1 in yourjson[n])
for(n1_2 in yourjson[n][n1_1])
obj[n1_2[name]] = n1_2[value];
Approved code
for(n1 in yourobj){
for(n1_1 in yourobj[n1]){
for(n1_2 in yourobj[n1][n1_1]){
for(n1_3 in yourobj[n1][n1_1][n1_2]){
obj[yourobj[n1][n1_1][n1_2].name]=yourobj[n1][n1_1][n1_2].value;
}
}
}
}
console.log(obj);
result
*You should use distinguish accessorizes when using [] method or dot notation
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