Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

json_encode/json_decode - returns stdClass instead of Array in PHP

Tags:

json

php

People also ask

Does json_decode return array?

json - json_decode does not return array in php - Stack Overflow. Stack Overflow for Teams – Start collaborating and sharing organizational knowledge.

What does json_decode return?

The json_decode() function can return a value encoded in JSON in appropriate PHP type. The values true, false, and null is returned as TRUE, FALSE, and NULL respectively. The NULL is returned if JSON can't be decoded or if the encoded data is deeper than the recursion limit.

What does the PHP function json_encode () do?

PHP | json_encode() Function The json_encode() function is an inbuilt function in PHP which is used to convert PHP array or object into JSON representation.

What is json_encode and json_decode?

JSON data structures are very similar to PHP arrays. PHP has built-in functions to encode and decode JSON data. These functions are json_encode() and json_decode() , respectively. Both functions only works with UTF-8 encoded string data.


Take a closer look at the second parameter of json_decode($json, $assoc, $depth) at https://secure.php.net/json_decode


$arrayDecoded = json_decode($arrayEncoded, true);

gives you an array.


To answer the actual question:

Why does PHP turn the JSON Object into a class?

Take a closer look at the output of the encoded JSON, I've extended the example the OP is giving a little bit:

$array = array(
    'stuff' => 'things',
    'things' => array(
        'controller', 'playing card', 'newspaper', 'sand paper', 'monitor', 'tree'
    )
);
$arrayEncoded = json_encode($array);
echo $arrayEncoded;
//prints - {"stuff":"things","things":["controller","playing card","newspaper","sand paper","monitor","tree"]}

The JSON format was derived from the same standard as JavaScript (ECMAScript Programming Language Standard) and if you would look at the format it looks like JavaScript. It is a JSON object ({} = object) having a property "stuff" with value "things" and has a property "things" with it's value being an array of strings ([] = array).

JSON (as JavaScript) doesn't know associative arrays only indexed arrays. So when JSON encoding a PHP associative array, this will result in a JSON string containing this array as an "object".

Now we're decoding the JSON again using json_decode($arrayEncoded). The decode function doesn't know where this JSON string originated from (a PHP array) so it is decoding into an unknown object, which is stdClass in PHP. As you will see, the "things" array of strings WILL decode into an indexed PHP array.

Also see:

  • RFC 4627 - The application/json Media Type for JavaScript Object
  • RFC 7159 - The JavaScript Object Notation (JSON) Data Interchang
  • PHP Manual - Arrays

Thanks to https://www.randomlists.com/things for the 'things'


Although, as mentioned, you could add a second parameter here to indicate you want an array returned:

$array = json_decode($json, true);

Many people might prefer to cast the results instead:

$array = (array)json_decode($json);

It might be more clear to read.


tl;dr: JavaScript doesn't support associative arrays, therefore neither does JSON.

After all, it's JSON, not JSAAN. :)

So PHP has to convert your array into an object in order to encode into JSON.


    var_dump(json_decode('{"0":0}'));    // output: object(0=>0)
    var_dump(json_decode('[0]'));          //output: [0]

    var_dump(json_decode('{"0":0}', true));//output: [0]
    var_dump(json_decode('[0]', true));    //output: [0]

If you decode the json into array, information will be lost in this situation.