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I am encoding my array into JSON and below is the case in which it gives Inf and NaN cannot be JSON encoded error
$test = ['key' => '6E01400'];
json_encode($test, JSON_NUMERIC_CHECK | JSON_PRETTY_PRINT);
I understand it considers 'E' in a key as an exponent and tries to convert into a number something like 6.0 e+1400...I don't know not sure though.
Is there anyway I can avoid that conversion for special case like this one, I really need to use JSON_NUMERIC_CHECK option here, any clue guys?
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The json_encode() function is used to encode a value to JSON format.
JSON data structures are very similar to PHP arrays. PHP has built-in functions to encode and decode JSON data. These functions are json_encode() and json_decode() , respectively. Both functions only works with UTF-8 encoded string data.
The json_encode() function can return a string containing the JSON representation of supplied value. The encoding is affected by supplied options, and additionally, the encoding of float values depends on the value of serialize_precision.
There is a workaround for this in PHP 5.5.0 and above so that you can still get JSON to output, but it does rewrite your data.
The JSON_PARTIAL_OUTPUT_ON_ERROR option can be set on json_encode, if you are getting back a JSON_ERROR_INF_OR_NAN. The PHP doc says that in the case of the NAN or INF value, "0 will be encoded in the place of these special numbers."
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