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JS function being called twice? [closed]

I can't seem to find the bug that's making the code run twice, and JSFiddle isn't working for me so I can't double check if it's the editor.

var friends = {};
friends.bill = {
    firstName: "Bill",
    lastName: "Gates",
    number: 9,
    address: ["5242", "drank avenue"]
};
friends.steve = {
    firstName: "Steve",
    lastName: "Jobs",
    number: 8,
    address: ["3368", "pool lane"]
};

var list = function(person)
{
    for (var friendName in person)
        console.log(friendName);
};

list(friends);

Output:
bill
steve
bill
steve
like image 704
stumped Avatar asked Aug 22 '14 09:08

stumped


1 Answers

I cut and pasted the code you posted into my JavaScript console and the result was:

bill
steve

Somewhere, in your original code, you must be calling the function twice.

Choose a place in the code — in this case I would choose the top of your list function — and put a

debugger;

statement there, and open the JavaScript console.

There will be an option in that debugger to see a stack trace. The stack trace will let you see exactly where a function was called from, so you can see if it is being called from two different points.

If that doesn't work, move the debugger statement to right above this line:

friends.bill = {

and repeat until you find the problem.

like image 113
Jeremy J Starcher Avatar answered Sep 21 '22 19:09

Jeremy J Starcher