Following this post jQuery table sort (github link: https://github.com/padolsey/jQuery-Plugins/blob/master/sortElements/jquery.sortElements.js), I am successfully sort columns, however it does not work in the case of rowspan: For example, case like this
Grape 3,096,671M
1,642,721M
Apple 2,602,750M
3,122,020M
When I click on the second column, it try to sort
Apple 2,602,750M
1,642,721M
Grape 3,096,671M
3,122,020M
(Expected result should be that it should only sort within each rowspan
Grape 1,642,721M
3,096,671M
Apple 2,602,750M
3,122,020M
or
Grape 3,096,671M
1,642,721M
Apple 3,122,020M
2,602,750M
)
so either which as you can see is not correct, please any jQuery guru help me fix this problem. Here is my code
var inverse = false;
function sortColumn(index){
index = index + 1;
var table = jQuery('#resultsTable');
table.find('td').filter(function(){
return jQuery(this).index() == index;
}).sortElements(function(a, b){
a = convertToNum($(a).text());
b = convertToNum($(b).text());
return (
isNaN(a) || isNaN(b) ?
a > b : +a > +b
) ?
inverse ? -1 : 1 :
inverse ? 1 : -1;
},function(){
return this.parentNode;
});
inverse = !inverse;
}
function convertToNum(str){
if(isNaN(str)){
var holder = "";
for(i=0; i<str.length; i++){
if(!isNaN(str.charAt(i))){
holder += str.charAt(i);
}
}
return holder;
}else{
return str;
}
}
Question:
1.How do I sort this with rowspan. THE NUMBER OF ROWSPAN IS NOT ALWAYS THE SAME. The above example both Grape and Apple have rowspan of 2, but this is not always the case.
2.Can any explain this syntax:
return (
isNaN(a) || isNaN(b) ?
a > b : +a > +b
) ?
inverse ? -1 : 1 :
inverse ? 1 : -1;
So I can see that if either a or b is not a number, then do string comparison otherwise do number comparison, but I dont understand the
inverse ? -1 : 1 :
inverse ? 1 : -1;
Test cases
<table id="resultsTable">
<thead>
<tr>
<th>Fruit</th>
<th onclick="sortColumn(1)">Quantity</th>
<th onclick="sortColumn(2)">Rate</th>
</tr>
</thead>
<tbody>
<tr>
<td rowspan="4">Grape</td>
<td>15</td>
<td>5</td>
</tr>
<tr>
<td>4</td>
<td>2</td>
</tr>
<tr>
<td>88</td>
<td>1</td>
</tr>
<tr>
<td>11</td>
<td>3</td>
</tr>
<tr>
<td rowspan="3">Melon</td>
<td>21</td>
<td>2</td>
</tr>
<tr>
<td>2</td>
<td>0</td>
</tr>
<tr>
<td>35</td>
<td>1</td>
</tr>
<tr>
<td rowspan="6">Melon</td>
<td>24</td>
<td>5</td>
</tr>
<tr>
<td>66</td>
<td>2</td>
</tr>
<tr>
<td>100</td>
<td>4</td>
</tr>
<tr>
<td>21</td>
<td>1</td>
</tr>
<tr>
<td>65</td>
<td>3</td>
</tr>
<tr>
<td>2</td>
<td>0</td>
</tr>
</tbody>
<table>
Conditions for the code to work:
td
s with rowspan
must all be on the left of the tabletd
s in these columns must have a rowspan
, even if it's 1jsFiddle: http://jsfiddle.net/5GrAC/77/
var inverse = false;
function sortColumn(index) {
var trs = $('#resultsTable > tbody > tr'),
nbRowspans = trs.first().children('[rowspan]').length,
offset = trs.first().children('[rowspan]').last().offset().left;
var tds = trs.children('[rowspan]').each(function() {
$(this).data('row', $(this).parent().index());
$(this).data('column', $(this).index());
$(this).data('offset', $(this).offset().left)
}).each(function() {
if($(this).data('offset') != offset)
return;
var rowMin = $(this).data('row'),
rowMax = rowMin + parseInt($(this).attr('rowspan'));
trs.slice(rowMin, rowMax).children().filter(function() {
return $(this).index() == index + $(this).parent().children('[rowspan]').length - nbRowspans;
}).sortElements(function(a, b) {
a = convertToNum($(a).text());
b = convertToNum($(b).text());
return (
isNaN(a) || isNaN(b) ?
a > b : +a > +b
) ?
inverse ? -1 : 1 :
inverse ? 1 : -1;
}, function() {
return this.parentNode;
});
});
var trs = $('#resultsTable > tbody > tr');
tds.each(function() {
if($(this).parent().index() != $(this).data('row'))
$(this).insertBefore(trs.eq($(this).data('row')).children().eq($(this).data('column')));
});
inverse = !inverse;
}
Quick explanations:
td
s with rowspan
td
s are saved, including left offsettd
s are filtered by their original offset
to work only with the rightmost onestr
s related to each kept td
are sorted using the wanted columntd
s with rowspan
are finally moved back to their original position if necessaryAbout question 2, I will only complete bartlaarhoven's answer by saying, the code can also be written like the following:
return (
(isNaN(a) || isNaN(b) ? a > b : +a > +b) ? 1 : -1
) * (inverse ? -1 : 1);
You can easily read that inverse
is used to inverse the result.
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