jQuery - Count list children not containing div with class

Question

I have a simple js script that counts the number of children an unordered list has. I'm trying to change the script so it doesn't count any children (li) which contain a div with the class 'hiddenItem'. Here's the list and the js.

    <ul id="dlist" class="sortable">
        <li id="listItem_000002">
            <div>
                <div><a class="itemCollapse"></a>
                </div>Item 2</div>
        </li>
        <li id="listItem_000003">
            <div>
                <div><a class="itemCollapse"></a>
                </div>Item 3</div>
        </li>
        <li id="listItem_000009">
            <div>
                <div><a class="itemCollapse"></a>
                </div>Item 9</div>
        </li>
        <li id="listItem_000012">
            <div class="hiddenItem">
                <div><a class="itemCollapse"></a>
                </div>Item 12 (Hidden)</div>
        </li>
    </ul>
    <br>
    <br>

    <a class="count">Count</a>

.

    $(".count").click(function () {
        var tcount = $("#dlist").children("li").length;
        alert(tcount);
    });

In this example the js alerts that there are 4 items. But, I'm trying to change the code so it alerts 3 items, due to the last list item containing the div with the class 'hiddenItem.' I've tried to use .filter() as well as a few other transverseing methods with no luck. Anyone have a better idea?

Here's a working fiddle: http://jsfiddle.net/YeDdq/1/

Any help would be appreciated. Thanks!

Answer 1

You can use not method.

var tcount = $("#dlist > li").not(':has(div.hiddenItem)').length;

Or filter method:

var tcount = $("#dlist > li").filter(function(){
                 return $('div.hiddenItem', this).length === 0;
             }).length;

Answer 2

.not works, and it's more readable:

$('#dlist > li').not('.hiddenItem').length;

Edit: just realized the first answer also has .not listed, but I'm not sure why they made it so complicated with the has pseudo-class.