<jdbc:embedded-database> in context.xml does not work. Want to to start an sql script for unit testing

Question

Here is my context file.:

<beans default-lazy-init="true" xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/tx
    http://www.springframework.org/schema/tx/spring-tx-3.0.xsd http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc.xsd"
       xmlns:jdbc="http://www.springframework.org/schema/jdbc"> <!--Line 11-->

<tx:annotation-driven transaction-manager="transactionManager"/>



<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">    <!---->
    <property name="driverClassName" value="org.hsqldb.jdbc.JDBCDriver"/>
    <property name="url" value="jdbc:hsqldb:mem:mydb"/>
    <property name="username" value="sa"/>
    <property name="password" value=""/>
</bean>

<bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
    <property name="dataSource" ref="dataSource"/>
    <property name="configLocation" value="hibernate.cfg.xml.incDTD"/>
    <property name="hibernateProperties">
        <props>
            <prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop>
            <prop key="hibernate.hbm2ddl.auto">create</prop>
            <prop key="hibernate.show_sql">true</prop>
            <prop key="hibernate.connection.shutdown">true</prop>
        </props>
    </property>
</bean>

<bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory"/>
 </bean>

<jdbc:embedded-database id="embedded" type="HSQL"/>
<jdbc:initialize-database data-source="dataSource">
    <jdbc:script location="classpath:ctl_data-scrubd.sql"/>
</jdbc:initialize-database>

I get this error

Caused by: org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: Line 11 in XML document from class path resource [PersistenceHelper-context.xml] is invalid; nested exception is org.xml.sax.SAXParseException; lineNumber: 11; columnNumber: 64; <Line 11, Column 64>: XML-24500: (Error) Can not build schema 'http://www.springframework.org/schema/jdbc' located at 'http://www.springframework.org/schema/jdbc/spring-jdbc.xsd'

I want to start an sql script for testing. I need to start it from inside this xml file. I have read using by it does not work. Does anyone know how I can fix this problem, or an alternative way to start an .sql file from inside. If you want to see more of my code, please let me know.

Edit::

I posted this same question on another site, and I got some suggestions. The error is now:

at org.junit.runners.ParentRunner.run(ParentRunner.java:220)
at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.run(SpringJUnit4ClassRunner.java:174)
at org.junit.runner.JUnitCore.run(JUnitCore.java:137)
at com.intellij.junit4.JUnit4IdeaTestRunner.startRunnerWithArgs(JUnit4IdeaTestRunner.java:76)
at com.intellij.rt.execution.junit.JUnitStarter.prepareStreamsAndStart(JUnitStarter.java:195)
at com.intellij.rt.execution.junit.JUnitStarter.main(JUnitStarter.java:63)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120)
Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean   with name 'org.springframework.jdbc.datasource.init.DataSourceInitializer#0': Invocation of init method failed; nested exception is org.springframework.dao.DataAccessResourceFailureException: Failed to execute database script; nested exception is org.springframework.jdbc.datasource.init.ScriptStatementFailedException: Failed to execute SQL script statement at line 1 of resource class path resource []: bin
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean

Here is my config file now as well. All I did was add a version and move some of the declarations around:

<?xml version="1.0" encoding="UTF-8"?>
<!-This is the spring configuration file for test cases.-->
<beans default-lazy-init="true" xmlns="http://www.springframework.org/schema/beans"
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xmlns:tx="http://www.springframework.org/schema/tx"
   xmlns:jdbc="http://www.springframework.org/schema/jdbc"
   xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/jdbc
http://www.springframework.org/schema/jdbc/spring-jdbc-3.0.xsd">

<tx:annotation-driven transaction-manager="transactionManager"/>

All the rest is the same.

Answer 1

Just to complete the answers, that's the context which works for me (Spring 3.2.1):

<beans xmlns="http://www.springframework.org/schema/beans"
            xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
            xmlns:jdbc="http://www.springframework.org/schema/jdbc"
            xsi:schemaLocation="http://www.springframework.org/schema/beans
                                                    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                                                    http://www.springframework.org/schema/jdbc
                                                    http://www.springframework.org/schema/jdbc/spring-jdbc-3.0.xsd">
    <jdbc:embedded-database id="dataSource" type="HSQL">
        <jdbc:script location="classpath:schema.sql" />
        <jdbc:script location="classpath:data.sql" />
    </jdbc:embedded-database>
</beans>

Answer 2

Fixed this by moving the definition xmlns:jdbc="http://www.springframework.org/schema/jdbc" to the top and by adding a version number "spring-jdbc-3.0.xsd" to the definition.