I have the following XML:
<mappings>
<mapping>
<parameter attr = "value">asdas</parameter>
<parameter attr = "value2">d123asdsad</parameter>
<parameter attr = "value3">0</parameter>
</mapping>
<mapping>
<parameter attr = "value">23123s</parameter>
<parameter attr = "value2">qwerty</parameter>
<!-- more parameter elements -->
</mapping>
<!-- more mapping elements -->
</mappings>
I have the following java classes to map it to:
@XmlRootElement(name = "mappings")
public class Mappings {
@XmlElement(name = "mapping")
private List<Mapping> mMappings;
public List<Mapping> getMappings() {
return mMappings;
}
public void setMappings(List<Mapping> aMappings) {
this.mMappings = aMappings;
}
}
public class Mapping {
@XmlElement(name = "parameter")
private List<Parameter> mParameters;
public List<Parameter> getParameters() {
return mParameters;
}
public void setParameters(List<Parameter> aParameters) {
this.mParameters = aParameters;
}
}
public class Parameter {
@XmlAttribute(name = "attr")
private String mName;
@XmlValue
private String mValue;
public String getName() {
return mName;
}
public void setName(String aName) {
this.mName = aName;
}
public String getValue() {
return mValue;
}
public void setValue(String aValue) {
this.mValue = aValue;
}
}
When I try to unmarshall it with
JAXBContext context = JAXBContext.newInstance(BundleMappings.class);
Unmarshaller um = context.createUnmarshaller();
mappings = (BundleMappings)um.unmarshal(new File(myFile));
I get this error
If a class has @XmlElement property, it cannot have @XmlValue property.
I need parameter to have both the 'attr' attribute and content, so what am I doing wrong?
Annotation Type XmlAccessorTypeControls whether fields or Javabean properties are serialized by default. Usage. @XmlAccessorType annotation can be used with the following program elements: package. a top level class.
A JavaBean property, when annotated with @XmlElement annotation is mapped to a local element in the XML Schema complex type to which the containing class is mapped.
Bind the Schema. JAXB simplifies access to an XML document from a Java program by presenting the XML document to the program in a Java format. The first step in this process is to bind the schema for the XML document into a set of Java classes that represents the schema.
By default JAXB (JSR-222) implementations consider public properties (get/set methods) and annotated fields as mapped (and separate). The default mapping is @XmlElement
so your properties will be considered as mapped this way.
Solution #1
Since you are annotating the fields you need to add @XmlAccessorType(XmlAccessType.FIELD)
on your classes.
@XmlAccessorType(XmlAccessType.FIELD)
public class Parameter {
@XmlAttribute(name = "attr")
private String mName;
@XmlValue
private String mValue;
public String getName() {
return mName;
}
public void setName(String aName) {
this.mName = aName;
}
public String getValue() {
return mValue;
}
public void setValue(String aValue) {
this.mValue = aValue;
}
}
Solution #2
Annotate the get (or set) methods.
public class Parameter {
private String mName;
private String mValue;
@XmlAttribute(name = "attr")
public String getName() {
return mName;
}
public void setName(String aName) {
this.mName = aName;
}
@XmlValue
public String getValue() {
return mValue;
}
public void setValue(String aValue) {
this.mValue = aValue;
}
}
For More Information
UPDATE
You will also need to use the @XmlElement
annotation on the mappings
property to specify the element name should be mapping
.
@XmlRootElement(name = "mappings")
public class Mappings {
private List<Mapping> mMappings;
@XmlElement(name="mapping")
public List<Mapping> getMappings() {
return mMappings;
}
public void setMappings(List<Mapping> aMappings) {
this.mMappings = aMappings;
}
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With