Javascript sort function. Sort by First then by Second

Question

I have an array of objects to sort. Each object has two parameters: Strength and Name

objects = [] object[0] = {strength: 3, name: "Leo"} object[1] = {strength: 3, name: "Mike"} 

I want to sort first by Strength and then by name alphabetically. I am using the following code to sort by the first parameter. How do I sort then by the second?

function sortF(ob1,ob2) {   if (ob1.strength > ob2.strength) {return 1}   else if (ob1.strength < ob2.strength){return -1}   return 0; }; 

Thanks for your help.

(I am using Array.sort() with the aforementioned sortF as the sort comparison function passed into it.)

Answer 1

Expand your sort function to be like this;

function sortF(ob1,ob2) {     if (ob1.strength > ob2.strength) {         return 1;     } else if (ob1.strength < ob2.strength) {          return -1;     }      // Else go to the 2nd item     if (ob1.name < ob2.name) {          return -1;     } else if (ob1.name > ob2.name) {         return 1     } else { // nothing to split them         return 0;     } } 

A < and > comparison on strings is an alphabetic comparison.