JavaScript: Round to a number of decimal places, but strip extra zeros

Question

Here's the scenario: I'm getting .9999999999999999 when I should be getting 1.0.
I can afford to lose a decimal place of precision, so I'm using .toFixed(15), which kind of works.

The rounding works, but the problem is that I'm given 1.000000000000000.
Is there a way to round to a number of decimal places, but strip extra whitespace?

Note: .toPrecision isn't what I want; I only want to specify how many numbers after the decimal point.
Note 2: I can't just use .toPrecision(1) because I need to keep the high precision for numbers that actually have data after the decimal point. Ideally, there would be exactly as many decimal places as necessary (up to 15).

Answer 1

>>> parseFloat(0.9999999.toFixed(4)); 1 >>> parseFloat(0.0009999999.toFixed(4)); 0.001 >>> parseFloat(0.0000009999999.toFixed(4)); 0 

Answer 2

Yes, there is a way. Use parseFloat().

parseFloat((1.005).toFixed(15)) //==> 1.005 parseFloat((1.000000000).toFixed(15)) //==> 1 

See a live example here: http://jsfiddle.net/nayish/7JBJw/