javascript regex for string starting with forward slash followed by alphanum chars and no space

Question

Need a JavaScript regular expression for validating a string that should start with a forward slash ("/") followed by alphanumeric characters with no spaces?

Answer 1

The regex you need is:

/^\/[a-z0-9]+$/i

i.e.:

• ^ - anchor the start of the string
• \/ - a literal forward slash, escaped
• [a-z0-9]+ - 1 or more letters or digits. You can also use \d instead of 0-9
• $ - up to the end of the string
• /i - case independent

Answer 2

This should do it. This takes a-z and A-Z and 0-9.

/^\/[a-z0-9]+$/i

Image from Regexper.com

Answer 3

Try following:

/^\/[\da-z]+$/i.test('/123')    // true
/^\/[\da-z]+$/i.test('/blah')   // true
/^\/[\da-z]+$/i.test('/bl ah')  // false
/^\/[\da-z]+$/i.test('/')       // false