Is there a simple way to check how many times a character appears in a String?
My favorite way to count how many times a character appears in a String is str. split("x"). length - 1 , where str is the String and "x" is the character you are searching for. The way this work is that the "split" method in Javascript splits the String into an array of substrings.
First, we split the string by spaces in a. Then, take a variable count = 0 and in every true condition we increment the count by 1. Now run a loop at 0 to length of string and check if our string is equal to the word.
you can use . indexOf() and . lastIndexOf() to determine if an index is repeated. Meaning, if the first occurrence of the character is also the last occurrence, then you know it doesn't repeat.
One of the solution can be provided by the match() function, which is used to generate all the occurrences of a string in an array. By counting the array size that returns the number of times the substring present in a string.
You could remove any other character in the string and check the length:
str.replace(/[^a]/g, "").length
Here it is counted how many a
s are in str
. The RegExp
is described below:
[ // Start Character Group ^ // Not operator in character group a // The character "a" ] // End character group
This counts a
in below example:
str = "A man is as good as his word"; alert(str.split('a').length-1);
If you want case insensitive you'd want something like
alert(str.split( new RegExp( "a", "gi" ) ).length-1);
So that it grabs "A" and "a" ... "g" flag isn't really needed, but you do need the "i" flag
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