javascript: get subarray from an array by indexes

Question

Is there a one-line code to get an subarray from an array by index?

For example, suppose I want to get ["a","c","e"] from ["a","b","c","d","e"] by [0,2,4]. How to do this with a one-line code? Something like ["a","b","c","d","e"][0,2,4]..

Answer 1

You could use map;

var array1 = ["a","b","c"];
var array2 = [0,2];
var array3 = array2.map(i => array1[i]);
console.log(array3);

Answer 2

You can use filter

const arr = ['a', 'b', 'c'];
const indexes = [0, 2];

const result = arr.filter((elt, i) => indexes.indexOf(i) > -1);

document.body.innerHTML = result;

Answer 3

You can use a combination of Array#filter and Array#includes

const array = ['a','b','c'];
console.log(array.filter((x,i) => [0,2].includes(i)));

Answer 4

You can use Array.prototype.reduce()

const arr = ['a', 'b', 'c', 'd', 'e'];
const indexes = [0, 2, 4];

const result = indexes.reduce((a, b)=> {
a.push(arr[b]);
return a;
}, []);

console.log(result);