Javascript function to convert indian currency numbers to words with paise support

Question

Is there any faster solution than this?

After spending some time in googling and playing with other's code, I made a quick fix and reusable function works well for numbers up to 99,99,99,999.

number2text(1234.56); will return ONE THOUSAND TWO HUNDRED AND THIRTY-FOUR RUPEE AND FIFTY-SIX PAISE ONLY .

function number2text(value) {
    var fraction = Math.round(frac(value)*100);
    var f_text  = "";

    if(fraction > 0) {
        f_text = "AND "+convert_number(fraction)+" PAISE";
    }

    return convert_number(value)+" RUPEE "+f_text+" ONLY";
}

function frac(f) {
    return f % 1;
}

function convert_number(number)
{
    if ((number < 0) || (number > 999999999)) 
    { 
        return "NUMBER OUT OF RANGE!";
    }
    var Gn = Math.floor(number / 10000000);  /* Crore */ 
    number -= Gn * 10000000; 
    var kn = Math.floor(number / 100000);     /* lakhs */ 
    number -= kn * 100000; 
    var Hn = Math.floor(number / 1000);      /* thousand */ 
    number -= Hn * 1000; 
    var Dn = Math.floor(number / 100);       /* Tens (deca) */ 
    number = number % 100;               /* Ones */ 
    var tn= Math.floor(number / 10); 
    var one=Math.floor(number % 10); 
    var res = ""; 

    if (Gn>0) 
    { 
        res += (convert_number(Gn) + " CRORE"); 
    } 
    if (kn>0) 
    { 
            res += (((res=="") ? "" : " ") + 
            convert_number(kn) + " LAKH"); 
    } 
    if (Hn>0) 
    { 
        res += (((res=="") ? "" : " ") +
            convert_number(Hn) + " THOUSAND"); 
    } 

    if (Dn) 
    { 
        res += (((res=="") ? "" : " ") + 
            convert_number(Dn) + " HUNDRED"); 
    } 


    var ones = Array("", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX","SEVEN", "EIGHT", "NINE", "TEN", "ELEVEN", "TWELVE", "THIRTEEN","FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN","NINETEEN"); 
var tens = Array("", "", "TWENTY", "THIRTY", "FOURTY", "FIFTY", "SIXTY","SEVENTY", "EIGHTY", "NINETY"); 

    if (tn>0 || one>0) 
    { 
        if (!(res=="")) 
        { 
            res += " AND "; 
        } 
        if (tn < 2) 
        { 
            res += ones[tn * 10 + one]; 
        } 
        else 
        { 

            res += tens[tn];
            if (one>0) 
            { 
                res += ("-" + ones[one]); 
            } 
        } 
    }

    if (res=="")
    { 
        res = "zero"; 
    } 
    return res;
}

Answer 1

INDIAN PRICE CURRENCY BY WORDS BASED ON GIVEN NUMBER

125,00,00,000

One Hundred and Twenty Five Crore

function price_in_words(price) {
  var sglDigit = ["Zero", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"],
    dblDigit = ["Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"],
    tensPlace = ["", "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"],
    handle_tens = function(dgt, prevDgt) {
      return 0 == dgt ? "" : " " + (1 == dgt ? dblDigit[prevDgt] : tensPlace[dgt])
    },
    handle_utlc = function(dgt, nxtDgt, denom) {
      return (0 != dgt && 1 != nxtDgt ? " " + sglDigit[dgt] : "") + (0 != nxtDgt || dgt > 0 ? " " + denom : "")
    };

  var str = "",
    digitIdx = 0,
    digit = 0,
    nxtDigit = 0,
    words = [];
  if (price += "", isNaN(parseInt(price))) str = "";
  else if (parseInt(price) > 0 && price.length <= 10) {
    for (digitIdx = price.length - 1; digitIdx >= 0; digitIdx--) switch (digit = price[digitIdx] - 0, nxtDigit = digitIdx > 0 ? price[digitIdx - 1] - 0 : 0, price.length - digitIdx - 1) {
      case 0:
        words.push(handle_utlc(digit, nxtDigit, ""));
        break;
      case 1:
        words.push(handle_tens(digit, price[digitIdx + 1]));
        break;
      case 2:
        words.push(0 != digit ? " " + sglDigit[digit] + " Hundred" + (0 != price[digitIdx + 1] && 0 != price[digitIdx + 2] ? " and" : "") : "");
        break;
      case 3:
        words.push(handle_utlc(digit, nxtDigit, "Thousand"));
        break;
      case 4:
        words.push(handle_tens(digit, price[digitIdx + 1]));
        break;
      case 5:
        words.push(handle_utlc(digit, nxtDigit, "Lakh"));
        break;
      case 6:
        words.push(handle_tens(digit, price[digitIdx + 1]));
        break;
      case 7:
        words.push(handle_utlc(digit, nxtDigit, "Crore"));
        break;
      case 8:
        words.push(handle_tens(digit, price[digitIdx + 1]));
        break;
      case 9:
        words.push(0 != digit ? " " + sglDigit[digit] + " Hundred" + (0 != price[digitIdx + 1] || 0 != price[digitIdx + 2] ? " and" : " Crore") : "")
    }
    str = words.reverse().join("")
  } else str = "";
  return str

}

console.log(price_in_words(1250000000));
console.log(price_in_words(9999999999));

Answer 2

The second comment has the solution. Just use:

var num =129000.9889;
var splittedNum =num.toString().split('.')
var nonDecimal=splittedNum[0]
var decimal=splittedNum[1]
var value=price_in_words(Number(nonDecimal))+" and 
"+price_in_words(Number(decimal))+" paise"