I have a form with some action and onsubmit values, which is submitted through a submit input tag. The problem is that it should be submittable by two buttons, so I wrote a function for the second button to change the action and onsubmit values of the form:
<a href="javascript:submitCompare()" class="submit">Compare</a>
function submitCompare()
{
document.myForm.action = "anotherAction.php";
document.myForm.onsubmit = function() {return countChecked()};
document.myForm.submit();
}
function countChecked()
{
var n = $(".reports input:checked").length;
if (n >= 3 ) {
alert ('You must select less than 3 reports.');
return false;
}
else return true;
}
After clicking on the Compare link it sends me to the anotherAction.php page correctly, but even when I have more than 2 selected checkboxes (which is the validation rule). Can somebody help me make the onsubmit function work correctly?
document.myForm.onsubmit = function() {return countChecked()};
should be
document.myForm.onsubmit = function( e ) {
e = e || window.event;
if ( !countChecked() ) {
e.preventDefault();
e.returnValue = false;
}
};
Returning false on a submit will just end any further function execution. You want to preventDefault submission behavior if you don't want it to submit.
It is a late reply, but if someone else is looking at this...
instead of:
document.myForm.onsubmit = function() {return countChecked()};
I think you wanted:
document.myForm.setAttribute("onsubmit", "return countChecked()");
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