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Java xsd validation of xml without namespace

I want to validate an XML file against an XSD schema. The XML files root element does not have any namespace or xsi details. It has no attributes so just <root>.

I have tried the following code from http://www.ibm.com/developerworks/xml/library/x-javaxmlvalidapi.html with no luck as I receive cvc-elt.1: Cannot find the declaration of element 'root'

SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");

File schemaFile = new File("schema.xsd");

Schema xsdScheme = factory.newSchema(schemaFile);

Validator validator = xsdScheme.newValidator();

Source source = new StreamSource(xmlfile);

validator.validate(source);

The xml validates fine with the namespace headers included etc (added via xmlspy), but I would have thought the xml namespace could be declared without having to manually edit the source file?

Edit and Solution:

public static void validateAgainstXSD(File file) {

    try {
        SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");

        File schemaFile = new File("path/to/xsd");

        Schema xsdScheme = factory.newSchema(schemaFile);

        Validator validator = xsdScheme.newValidator();

        SAXSource source = new SAXSource(
                new NamespaceFilter(XMLReaderFactory.createXMLReader()),
                new InputSource(new FileInputStream(file)));

        validator.validate(source,null);

    } catch (Exception e) {
        e.printStackTrace();
    }

}

protected static class NamespaceFilter extends XMLFilterImpl {

    String requiredNamespace = "namespace";

    public NamespaceFilter(XMLReader parent) {
        super(parent);
    }

    @Override
    public void startElement(String arg0, String arg1, String arg2, Attributes arg3) throws SAXException {
        if(!arg0.equals(requiredNamespace)) 
            arg0 = requiredNamespace;
        super.startElement(arg0, arg1, arg2, arg3);
    }       
}
like image 298
Alec Holmes Avatar asked Jun 07 '10 16:06

Alec Holmes


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1 Answers

You have two separate concerns you need to take care of:

  1. Declaring the namespace that your document uses.
  2. Putting an xsi:schemaLocation attribute in the file to give a hint (!) where the schema is.

You can safely skip the second part, as the location is really only a hint. You cannot skip the first part. The namespace declared in the XML file is matched against the schema. Important, this:

<xml> ... </xml>

Is not the same as this:

<xml xmlns="urn:foo"> ... </xml>

So you need to declare your namespace in the XML document, otherwise it will not correspond to your schema and you will get this error.

like image 173
xcut Avatar answered Sep 20 '22 15:09

xcut