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I want to see if a character in my string equals a certain other char value but I do not know what the char in the string is so I have used this:
if ( fieldNames.charAt(4) == "f" )
But I get the error:
"Operator '==' cannot be applied to 'char', 'jav.lang.String'"
But "g" == "h" seems to work and I know you can use '==' with char types.
Is there another way to do this correctly? Thanks!
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The "charAt is not a function" error occurs when we call the charAt() method on a value that is not a string. To solve the error, convert the value to a string using the toString() method or make sure to only call the charAt method on strings.
How do you check if a char is equal to another char in Java? In Java, you can use the char “equals()” method to compare two character values by passing a character as a parameter. It returns a boolean value, “true” or “false”, where true indicates the value and the case is equal, and false denotes its negation.
But char is not an Object type in Java, it is a primitive type, it does not have any method or properties, so to check equality they can just use the == equals operator.
charAt() returns a char, so the message was telling you that . equals() is not appropriate.
if ( fieldNames.charAt(4) == 'f' )
because "f" is a String and fieldNames.charAt(4) is a char. you should use 'f' for check char
"g" == "h" works because both g and h are Strings
and you shouldn't use "g" == "h" you should use "g".equals("h") instead .
you can use == for primitive data types like char,int,boolean....etc.but for the objects like String it's really different.
To know why read this
but you can use also
'g' == 'h'
you should wrap Strings by double quotation and char by single quotation
String s="g";
char c='g';
but char can only have one character but String can have more than one
String s="gg"; valid
char c='gg'; not valid
I was having the same problem, but I was able to solve it using:
if (str.substring(0,1).equals("x") )
the substring can be used in a loop str.substring(i, i + 1)
charAt(i).equals('x') will not work together
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